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3 years ago

(-yx^2)^2 • -2x^0y^3

Mathematics

1 answer:

sveticcg [70]3 years ago

6 0

(-yx^2)^2 • -2x^0y^3
= x^4y^2 (-2y^3)
= - 2x^4y^5

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The perpendicular bisectors of sides AC and BC of △ABC intersect side AB at points P and Q respectively , and intersect each oth

MakcuM [25]

The measure of ∠ACB will be 110°

Explanation

According to the diagram below, $DE$ and $DF$ are the perpendicular bisectors of $AC$ and $BC$ respectively and they intersect side $AB$ at points $P$ and $Q$ respectively.

So, $AE=CE$ and $CF=BF$

Now, according to the $SAS$ postulate, ΔAPE and ΔCPE are congruent each other. Also, ΔCFQ and ΔBFQ are congruent to each other.

That means, ∠PCE = ∠PAE and ∠FCQ = ∠FBQ

As ∠CPQ = 78° , so ∠PCE + ∠PAE = 78° or, ∠PCE = $\frac{78}{2}=39$ ° and as ∠CQP = 62° , so ∠FCQ + ∠FBQ = 62° or, ∠FCQ = $\frac{62}{2}=31$ °

Now, in triangle CPQ, ∠PCQ = 180°-(78° + 62°) = 180° - 140° = 40°

Thus, ∠ACB = ∠PCE + ∠PCQ + ∠FCQ = 39° + 40° + 31° = 110°

5 0

3 years ago

Federico owns a care with a 18.4 gallon fuel tank. How many gallons are there in half

alex41 [277]

Answer:

9.2 gallons

Step-by-step explanation:

18.4/2 = 9.2 gallons

6 0

3 years ago

2y = 2x-4 y + 3x = 10 (substitution)

devlian [24]

Answer:

x = 3, y = 1

Step-by-step explanation:

2y = 2x - 4, so y = x - 2. Substituting this into the bottom equation and solving for x:

x - 2 + 3x = 10

4x - 2 = 10

4x = 12, so x = 3 and y = 1.

4 0

1 year ago

Compare the function ƒ(x) = –x2 + 4x – 5 and the function g(x), whose graph is shown. Which function has a greater absolute maxi

svp [43]

Answer:

A) g(x) has a greater absolute maximum.

Step-by-step explanation:

Given graph of g(x) which is a Parabola

1. Opens downwards

2. The absolute maximum (vertex) is at around (3.5, 6)

i.e. value of absolute maximum is 6.

Another function:

$f(x) =-x^{2}+4x-5$

Let us convert it to vertex form to find its vertex.

Taking - sign common:

$f(x) =-(x^{2}-4x+5)$

Now, let us try to make it a whole square,

Writing 5 as 4+1:

$f(x) =-(x^{2}-4x+4+1)\\\Rightarrow f(x) =-((x^{2}-2 \times 2\times x+2^2)+1)\\\Rightarrow f(x) =-((x-2)^{2}+1)\\\Rightarrow f(x) =-(x-2)^{2}-1$

Please refer to attached graph of f(x).

We know that, vertex form of a parabola is given as:

$f (x) = a(x - h)^2 + k$

Comparing the equations we get:

a = -1 (Negative value of a means the parabola opens downwards)

h = 2, k = -1

Vertex of f(x) is at (2, -1) i.e. value of absolute maximum is -1

and

Vertex of g(x) is at (3.5, 6)

i.e. value of absolute maximum is 6.

Hence, correct answer is:

A) g(x) has a greater absolute maximum.

3 0

3 years ago

Evaluate 1/x^-2 for x= 7. -49 49 1/49 Please help And thx but HURRY

ella [17]

Answer: 49

Step-by-Step Explanation:

As we can see, we have been given a negative exponent for “x”. Hence we have to take the reciprocal which would be x squared.

Therefore, x = 7
= x^2 = 7 * 7
= 49

5 0

2 years ago

Read 2 more answers