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4vir4ik [10]
1 year ago
13

I've done the y = equations but I don't know how to do this one.

Mathematics
1 answer:
Tems11 [23]1 year ago
6 0

Consider the equation

-10x-y=-20

1) First row of the table

Set x=0 and solve as follows:

\begin{gathered} -10(0)-y=-20 \\ \Rightarrow-y=-20 \\ \Rightarrow y=20 \end{gathered}

The answer is y=20 and the pair x-y is (0,20)

2) Second row

Set x=1 and solve, as follows:

\begin{gathered} -10(1)-y=-20 \\ \Rightarrow-10-y=-20 \\ \Rightarrow-y=-10 \\ \Rightarrow y=10 \end{gathered}

The answers are y=10 and (1,10)

3) Third row.

Set y=0 and solve as follows:

\begin{gathered} -10x-(0)=-20 \\ \Rightarrow-10x=-20 \\ \Rightarrow x=\frac{20}{10}=2 \\ \Rightarrow x=2 \end{gathered}

The answers are x=2 and (2,0)

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3 0
3 years ago
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Answer:

a

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$5 for a ticket means that slope =5.

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Answer is a.

8 0
3 years ago
Help me solve this by multiplication or linar combination please
patriot [66]
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4 0
3 years ago
A certain virus is dying off at a rate of 18% per hour. Initially there were
djyliett [7]

Answer:

3 strain would still alive after 48 hours

Step-by-step explanation:

Initial population of virus = 40000 grams

A certain virus is dying off at a rate of 18% per hour.

We are supposed to find  how much of the  strain would still be alive after 48 hours

Formula : N(t)=N_0(1-r)^t

N_0=Initial population

N(t)= Population after t hours

r = rate of decrease = 18% = 0.18

t = time = 48 hours

So,the  strain would still be alive after 48 hours=40000(1-0.18)^{48}=2.91 \sim 3

Hence 3 strain would still alive after 48 hours

3 0
3 years ago
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kifflom [539]
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hope it helps</span>
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