3 years ago

Can someone plz help me with this problem!!!

Mathematics

2 answers:

dsp733 years ago

8 0

Answer:

on the y axis

Step-by-step explanation:

pishuonlain [190]3 years ago

4 0

On the y axis it is going to be the bottom always

You might be interested in

What is the answer need helpp

Gre4nikov [31]

Hmm idk.... I need like more info for this please so I can help you thank you byeeeee

5 0

3 years ago

Select one: <br> A. Supplementary<br> B. Vertical<br> C. Complementary<br> D. Acute

Rom4ik [11]

Shouldnt there be a picture or something?

5 0

3 years ago

Use the drop-down menus to determine the best estimate for 5,984 ÷ 32.<br> Then find the quotient.

katrin [286]

Answer: 5,984 ÷ 32 = 0,187

Ok done. Thank to me :>

3 0

2 years ago

Find the value or measure. Assume all lines that appear to be tangent are tangent. X=

aev [14]

According to the secant-tangent theorem, we have the following expression:

$(x+3)^2=10.8(19.2+10.8)$

Now, we solve for <em>x</em>.

$\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}$

Then, we use the quadratic formula:

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where a = 1, b = 6, and c = -315.

$\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}$ <h2>Hence, the answer is 15 because lengths can't be negative.</h2>

7 0

1 year ago

Solve for y. 3/2x-3y=6

Vlada [557]

X=2(2+y) is your answer

3 0

2 years ago

Read 2 more answers