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xxMikexx [17]
1 year ago
14

Write three sentences that compare the values 12 and 3 in different ways

Mathematics
1 answer:
grin007 [14]1 year ago
6 0

Given data:

The numbers given are 12 and 3.

The 12 and 3 are both positive integers in which 12 is greater than 3.

The 12 and 3 both lie on the right side of the number line in which 12 comes after 3, so 12 is bigger number than 3.

The 12 and 3 are both natural as well as rational number, 12 is nine more than 3.

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I just need someone to convert those numbers to percentages. Thank you!
Nata [24]

Answer:

Middle school      High school

93%          36%

31%           54%

Step-by-step explanation:

this is over 100% btw

5 0
3 years ago
Solve linear equations -4(b+3)-12=2b-16+5b
daser333 [38]

Answer:

Exact form:b=-\frac{8}{11}\\Decimal form: b=-0.72727272727272727272

Step-by-step explanation:

-4(b+3)-12=2b-16+5b

-4b-12-12=2b+5b

-4b-24=7b-16

-4b=7b+8

3 0
4 years ago
Read 2 more answers
Constance was paid $67,452 this year (12 months) at her sales job. What were her monthly earnings (on average)?
weqwewe [10]

Answer:

To solve this problem, simply divide the total amount earned by the time in months it took to earn this total.

Therefore, divide the income of $67,452 by the 12 months it took to earn this much.

Your answer, B) $5,621.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Picture Included PLEASE help
OLEGan [10]
Is there any other answers? To me, none of those look correct. If you had -3 and substituted it into the equation you would get -1(-3)+3, which would turn into 3+3 which equals 6.
6 0
3 years ago
A chemical company makes two brands of antifreeze. The first brand is 60% pure antifreeze, and the second brand is 85% pure anti
rjkz [21]

Let’s say we have x gallons of brand 1 antifreeze and y gallons of brand 2 antifreeze. We know we need a total of 140 gallons, so one equation to relate the variables would be x+y=140. We also know that our final mixture should have 60% antifreeze, so another equation would be the weighted average of the two brands: .55x+.80y140=.60. (The weighted average is basically multiplying each % (55 and 80) by the number of gallons you have (x and y


) and adding those together, and dividing that by the total number of gallons (140). This equals the % of the final mixture (60).)


Now we have a system of two equations that we can solve.


x+y=140


.55x+.80y140=.60


*rearrange first equation to solve for y


:


y=140−x


*substitute this value in for y


in the second equation:


.55x+.80(140−x)140=.60


*use algebra and solve for x


:


The algebra shouldn’t be too complex, and I’m hoping you’re asking this about the setup rather than the actual algebra, and I’m lazy, and I used a calculator to solve this, and this is probably a long run-on sentence, and I got x=112


.


*plug this in to first equation and solve for y


:


y=140−112=28


x=112,y=28


112 gallons of brand 1 antifreeze, 28 gallons of brand 2 antifreeze. That’s a whole lot of antifreeze.

thanx heyaaaaaa

3 0
4 years ago
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