Solve linear equations -4(b+3)-12=2b-16+5b
2 answers:
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Answer:
The fractional change is % .
Step-by-step explanation:
Given as :
The original fraction =
Where numerator = x
Denominator = y
According to question
The numerator decreased by 50%
Let The new numerator = x' = x - 50% of x
I,e x' = x ( 1 - )
Or, x' = x ()
Or, x' = x
or, x' = .........A
Again
The new denominator = y' = y - 25% of y
i.e y' = y (1 - )
Or, y' = y ()
Or, y' = y ()
Or, y' = ............B
So, The new fraction = =
Or, =
So, The fractional change = × 100
Or, The fractional change = × 100
Hence, The fractional change is % . Answer
Answer:
The 80% confidence interval for the average net change is (8.596, 12.904).
Critical value t=1.638.
Step-by-step explanation:
First, we calculate the mean and standard deviation of the sample:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=10.75.
The sample size is N=4.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
The degrees of freedom for this sample size are:
The t-value for a 80% confidence interval and 3 degrees of freedom is t=1.638.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
The 80% confidence interval for the average net change is (8.596, 12.904).