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Irina18 [472]
1 year ago
7

Luke and isabella make scale drawings of a fountain. the scale from the fountain to isabella's drawing is 6 m to 3 cm. the heigh

t of the fountain in isabella's drawing is 5 cm. the scale from the fountain to luke's drawing is 5 m to 2 cm. what is the height of the fountain in luke's drawing?
Mathematics
1 answer:
alina1380 [7]1 year ago
7 0

In Luke's drawing, the height of the fountain is 4 cm. It is obtained after finding the real height of the fountain using the scale used by Isabella.

<h3>What is a scale?</h3>

A scale, in mathematics, is a ratio of the dimensions in a drawing to the actual dimensions. The formula is

<em>Scale = dimension in the drawing : actual dimension</em>

Given

  • The scale from the fountain to Isabella's drawing is 6 m to 3 cm
  • The height in Isabella's drawing = 5 cm
  • The scale from the fountain to Luke's drawing is 5 m to 2

What is the height of the fountain in Luke's drawing?

The scale used by Isabella

= 3 cm : 6 m

= 3 cm : 600 cm

= 1 : 200

The actual height of the fountain

= dimension in the drawing × scale

= 200 × 5

= 1.000 cm

The scale used by Luke

= 2 cm : 5 m

= 2 cm : 500 m

= 1 : 250

The height in Luke's drawing

= the actual height ÷ scale

= 1.000 ÷ 250

= 4 cm

Hence, in Luke's drawing, the height of the fountain is 4 cm.

Learn more about scale here:

brainly.com/question/16870997

#SPJ4

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-2x^2-x. Your answer was wrong because "x-squared" terms didn't cancel.

Step-by-step explanation:

To solve this problem, set up an equation.  We know something is supposed to be added to the expression 2x^2+2x, and the result should be x. So:

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2x^2+2x+(\text{ } y \text{ })=x

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<u>Understanding "terms" & "like terms"</u>

<u>Terms</u>

"Terms" in an equation are either a number multiplied to other things, or just a single number that isn't multiplied to anything else.

For example, the various terms in our equation above are

2x^2, 2x, y, x

You might ask why the last things, which don't have a number, are considered terms.

Remember that multiplying by 1 doesn't change anything, so we could imagine each of the last two terms as being 1 times the letter.

So, we can rewrite our equation:

 2x^2+2x+1y=1x

<u>Like terms</u>

"Like terms" are terms where the "other stuff the numbers are multiplied to" is the same, so for instance, the 2x and the 1x are like terms. They are like terms because, the "other stuff" that the numbers are multiplied to are "x" for both terms. Note that 2x and 2x^2 are not "like terms" because the "stuff" is different:

x is different than x^2

"Like terms" are important because only like terms can be "combined" into a single simplified term.

<u>Solving equations</u>

To solve an equation, we isolate what we're solving for, y, by disconnecting the other terms from it, and simplify.

Starting with subtracting 2x from both sides of the equation:

2x^2+2x+1y=1x\\(2x^2+2x+1y)-2x=(1x)-2x

Subtraction is the same as "adding a negative":

2x^2+2x+1y+(-2x)=1x+(-2x)

Since all terms are now connected by addition, we can add in any order we want (because of the Commutative Property of Addition), and we can combine like terms.

Thinking just about the number parts, since 1+(-2)=-1,  then 1x+(-2x)=-1x.

Returning to our main equation, the right side simplifies:

2x^2+2x+1y+(-2x)=1x+(-2x)\\2x^2+2x+1y+(-2x)=-1x

On the left side: 2x and -2x are like terms.

Fact: 2+(-2)=0

So, 2x+(-2x)=0x

Since anything times zero is just zero, 0x=0. Furthermore, adding zero to anything doesn't change it.  So when the 2x and -2x terms on the left side of our main equation are combined, they "disappear" <em>(While we talked through are a lot of rules/steps to justify why that works, it is common to omit those justifications, and to just combine those like terms and make them disappear.)</em>

So, 2x^2+2x+1y+(-2x)=-1x simplifies to:

2x^2+1y=-1x

Similarly for the 2x^2 term, we subtract from both sides:

2x^2+1y=-1x\\(2x^2+1y)-2x^2=(-1x)-2x^2\\2x^2+1y+(-2x^2)=-1x+(-2x^2)

Combining like terms on the left, they disappear.

1y=-1x+(-2x^2)

There are no like terms on the right.

Since the two terms on the right are added together, we can use the commutative property of addition to rearrange:

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Addition of a negative can turn back into subtraction, and simplify multiplication by 1.

y=-2x^2-x

Remembering we chose "y" as the unknown thing we wanted to know, that's why the "correct answer" is what it is.

<u>Verifying an answer</u>

Verifying can double check an answer, and helps explain why the answer you chose doesn't work.

To verify an answer, the original statement said add something to the expression and get a result of "x". So, let's see if the "correct answer" does:

2x^2+2x+(\text{ } ? \text{ })\\2x^2+2x+(-2x^2-x)\\2x^2+2x+(-2x^2-1x)\\2x^2+2x+(-2x^2)+(-1x)

Combining the "x-squared" terms, completely cancels...

2x+(-1x)

Combining the "x" terms, and simplifying...

1x\\x

So it works.

<u>Why isn't the answer what you chose:</u>

2x^2+2x+(\text{ } ? \text{ })\\2x^2+2x+(-x^2-x)\\2x^2+2x+(-1x^2-1x)\\2x^2+2x+(-1x^2)+(-1x)

Combining the x-squared terms, things don't completely cancel...

1x^2+2x+(-1x)

Combining the x terms...

1x^2+1x\\x^2+x

So adding the answer that you chose to the expression would not give a result of "x", which is why it is "wrong"

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