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3 years ago

Factor 3r6 – 11r5 – 20r1 completely. 3r6 – 11r) – 20r! - =

Mathematics

1 answer:

BabaBlast [244]3 years ago

5 0

Answer:

-57

Step-by-step explanation:

3r x 6-11r x 5-20r x 1 any expression multiplied by 1 remains the same always calculate the product.

multiply calculate

18r-55r-20r

collect like terms

-57

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Step-by-step explanation:

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12x3=36

3+6=9

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3 years ago

A line passes through (2,4) and (-2,2). find the value of y if (6,y) lies on the same line

katrin2010 [14]

Answer:

y = 6, rendering the coordinate pair: (6,6)

Step-by-step explanation:

We start by writing the equation of the line that passes through two given points on the plane: $(x_1,y_1)$ and $(x_2,y_2)$ beginning with finding the slope of the segment that joints the points using the slope formula: $slope=\frac{y_2-y_1}{x_2-x_1}$

Let's call $(x_1,y_1)$ = (2,4), and $(x_2,y_2)$ = (-2,2). Then we have the formula for the slope:

$slope=\frac{y_2-y_1}{x_2-x_1}=\frac{2-4}{-2-2} =\frac{-2}{-4} =\frac{1}{2}$

Now that we have the slope of the line, we can find the actual equation of the line by using one of the given points, and the "point-slope" form of a line with slope "m" and going through a point $(x_0,y_0)$ - which in our case we defie as one of our given points, let's say (2, 4):

$y-y_0=m\,(x-x_0)\\y-4=\frac{1}{2} (x-2)\\y-4=\frac{1}{2} x-1\\y=\frac{1}{2} x-1+4\\y=\frac{1}{2} x+3$

now we find what is the "y" value in such line that corresponds to an x-value of "6" to complete the coordinate pair (6, ?). For such we simply evaluate the equation above at x = 6:

$y=\frac{1}{2} x+3\\y=\frac{1}{2} (6)+3\\y=3+3\\y=6$

Therefore, y must be "6".

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3 years ago

Factor 3r6 – 11r5 – 20r1 completely. 3r6 – 11r) – 20r! - =​

Factor 3r6 – 11r5 – 20r1 completely. 3r6 – 11r) – 20r! - =