3 √10
I think since a^2+b^2=c^2
The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.
<h3>What are the proves?</h3>
1. To know collinear vectors:
∧ ⁻a ║ ⁻a
If ⁻b = ∧ ⁻a
then |⁻b| = |∧ ⁻a|
So one can say that line ⁻b and ⁻a are collinear.
2. If ⁻a and ⁻b are collinear
Assuming |b| length is 'μ' times of |⁻a |
Then | 'μ' ⁻a| = | 'μ' ⁻a|
So ⁻b = 'μ' ⁻a
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Answer:
a,b and dcbecause it equals 1
Step-by-step explanation:
you have to find something that is gonna divide by itself to get a postive number, so d wont work bc it would be 24 divided by 25
Answer:
I don't know angles at all please ask your teacher for help...
Step-by-step explanation:
The answer is B, 5/2
You convert 2 1/2 (a mixed number) into an improper fraction to get 5/2