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Nookie1986 [14]
3 years ago
7

How do I solve 1.06g-7=0.95

Mathematics
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

g=7.5

Step-by-step explanation:

1.06g-7=0.95

         +7  +7

1.06g=7.95

divide both sides by 1.06

g=7.5

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Rita has a loan of $45,580. This loan has a simple interest rate 4% per year . What is the amount of interest that rRta will be
Feliz [49]

Answer:

$1,823.2

Step-by-step explanation:

Simple interest is calculated using the formula

I = P X R X T

where I is the interest amount

P is the principal amount: 45,580.  

R is the interest rate which is 4 %, or 0.04%

T is time, One year.

I = $45,580 x 0.04 x 1

I = $1,823.2 x 1

I = $1,823.2

7 0
3 years ago
GAIQNFKDKER HELP PLZ
Softa [21]

Answer:

it's the first answer

Step-by-step explanation:

literally every other answer is ruled out because D is the greatest variable and can't be smaller than anything else

3 0
3 years ago
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otez555 [7]

Answer:

I need this answer as well

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
This equation shows how the total number of pieces Lamar has learned depends on the number of weeks he has taken piano lessons.
Dominik [7]

Answer:

19 weeks

Step-by-step explanation:

Given equation:

P = w

Where,

w = the number of weeks he has taken piano lessons

p = the total number of pieces he has learned

how many weeks of piano lessons will Lamar need before he will be able to play a total of 19 pieces?

Find w when p = 19

P = w

p = 19

Since P = w

19 = w

Therefore,

w = 19

Lamar need 19 weeks before he will be able to play a total of 19 pieces

3 0
2 years ago
A cyclist set out from a town P on a bearing of to a town Q, 5 km away. He then moves on a bearing of to a town R, 6km from Q.
zaharov [31]

The bearing of R from P is 019 and the distance |PR| is 8.75

<h3>The complete question</h3>

A cyclist set out from a town P on a bearing of 060 to a town Q, 5 km away. He then moves on a bearing of 345 to a town R, 6km from Q.

<h3>The diagram that represents the information</h3>

See attachment

<h3>The bearing of R from P</h3>

Start by calculating the distance PR using the following cosine ratio

PR² = PQ² + QR² - 2 * PQ * PR cos(Q)

Substitute known values

PR² = 5² + 6² - 2 * 5 * 6 cos(105)

Evaluate

PR² = 76.53

Take the square root of both sides

PR = 8.75

Next, calculate angle R using the following sine ratio

PQ/sin(R) = PR/sin(Q)

Substitute known values

5/sin(R) = 8.75/sin(105)

Evaluate the quotient

5/sin(R) = 9.06

Multiply both sides by sin(R)

9.06 * sin(R) = 5

Divide both sides by 9.06

sin(R) = 0.5519

Take the arc sin of both sides

R = sin⁻¹(0.5519)

Evaluate

R = 34

Calculate angle P using:

P = 180 - 34 - 105

P = 41

The bearing of R from P is then calculated as:

Bearing = 060 - 41

Evaluate

Bearing =  019

Hence, the bearing of R from P is 019

<h3>The distance |PR|​</h3>

In (b), we have:

PR = 8.75

Hence, the distance |PR| is 8.75

Read more about bearing and distance at:

brainly.com/question/15221233

#SPJ1

8 0
1 year ago
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