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Artyom0805 [142]
1 year ago
15

Atom A has an atomic number of 7, an atomic charge of +1, and an atomic mass of 14 amu. How many valence electrons are present i

n this atom?
Biology
1 answer:
DanielleElmas [232]1 year ago
6 0

The number of valence electrons present in an atom with an atomic number of 7, an atomic charge of +1, and an atomic mass of 14 amu is 5.

In order words, the element has 5 valence electrons. This element is confirmed nitrogen.

<h3>What is valence electron?</h3>

Valence electrons are those electrons which reside in the outermost shell of an atom of an element. That being said, they are electrons which are found at the last shell of electron orbit.

So therefore, the number of valence electrons present in an atom with an atomic number of 7, an atomic charge of +1, and an atomic mass of 14 amu is 5.

In order words, the element has 5 valence electrons. This element is confirmed nitrogen.

Learn more about valence electrons:

brainly.com/question/371590

#SPJ1

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Alenkinab [10]

Answer:

The arteries (red) carry oxygen and nutrients away from your heart, to your body's tissues. The veins (blue) take oxygen-poor blood back to the heart. Arteries begin with the aorta, the large artery leaving the heart. They carry oxygen-rich blood away from the heart to all of the body's tissues.

Explanation:

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7 0
2 years ago
There are 100 cats in a population that follows hardy-weinberg conditions. 4 cats display a recessive white coat color. how many
mr Goodwill [35]

We know that Hardy-Weinberg conditions include the following equations:


p^{2}+2pq+ q^{2}=1


where p+q=1


And where p = dominant, and q = recessive; this means that p^{2} is equal to the homozygous dominant, 2pq is the heterozygous, and q^{2} is the homozygous recessive .


So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of \frac{4}{100} or 0.04. Let that equal our q^{2} value.


So when we solve for q, we get:


q^{2}=0.04

q=\sqrt{0.04} =0.2


Now that we have our q value, we can use the other equation to find p:


p+q=1


p+0.2=1


p=0.8


So then we can solve for our heterozygous population:


2pq=2(0.8)(0.2)=0.32


This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:


0.32*100=32cats


So now we know that there are 32 heterozygous cats in the population.

8 0
3 years ago
Alice's teacher has given her a cup of water. She needs to find the volume of the water. How can Alice find the volume of the wa
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6 0
3 years ago
How many calories can i eat without gaining weight?
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I think that a<span>n average woman needs to eat about 2000 calories per day to maintain, and 1500 calories to lose one pound of weight per week. An average man needs 2500 calories to maintain, and 2000 to lose one pound of weight per week</span>
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