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docker41 [41]
1 year ago
10

The point A(4, 1) is reflected over the point (0, -3) and its image is point B. What are the coordinates of point B?

Mathematics
1 answer:
omeli [17]1 year ago
4 0

A reflection over the point (0,0) is given by:

(x,y)\rightarrow(-x,-y)

Nevertheless, the reflection is being made over the point (0,-3). We can first make a traslation of the point (0,-3) to the origin. Then, reflect the new coordinates of the point A through the origin and then bring back the new origin to (0,-3).

First, make a traslation such that the new coordinates of (0,-3) are (0,0):

(x,y)\rightarrow(x,y+3)

Then, apply a reflection through the origin:

(x,y+3)\rightarrow(-x,-y-3)

Finally, make a traslation reciprocal to the first one:

(-x,-y-3)\rightarrow(-x,-y-3-3)=(-x,-y-6)

Therefore, the reflection over the point (0,-3) can be written as:

(x,y)\rightarrow(-x,-y-6)

Substitute (x,y)=(4,1) to find out the new coordinates of A after the reflection:

\begin{gathered} A\rightarrow B \\ \Rightarrow(4,1)\rightarrow(-4,-1-6)=(-4,-7) \end{gathered}

Therefore, the coordinates of the point B are (-4,-7).

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Write an equation of the circle with center (-7, 4) and radius 8.
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answer

(x+7)^2 + (y-4)^2 = 64

set up equation

the equation of a circle is (x - h)^2 + (y - k)^2 = r^2

where h is the center x coordinate and k is the center y coordinate

values

from the point (-7,4) we know that h = -7 and k = 4

since the radius is 8, r^2 = 8^2 = 64

plug in values

now that we have all the values, we plug them into (x - h)^2 + (y - k)^2 = r^2

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