I'm guessing you're asking what shape do you get if you cut a hexagon is cut into sixths.
If this hexagon is a regular hexagon, then the shapes would be equilateral triangles.
Answer:
The equation of the required line is y = x + 5
Step-by-step explanation:
The equation of the given line is y = x - 2
The required line = A line parallel to the given line
The point through which the required line passes = (-3, 2)
The general form of the equation of a straight line, is y = m·x + c
Where;
m = The slope of the line
By comparison, the slope of the given line, m = 1
When two lines are parallel, their slope are equal
Therefore, the slope of the required line = m = 1
The equation of the required line in point and slope form is therefore;
y - 2 = x - (-3) = x + 3
∴y = x + 3 + 2 = x + 5
The equation of the required line is therefore;
y = x + 5.
Answer:
Step-by-step explanation:
m has a slope of -2 and a y intercept of 4
y = -2x + 4
n has a slope of 1 and a y intercept of -1
y = 1x - 1
y = x - 1
Ah!... the invisible questions in a sideways posted image.
t has a slope of zero and a y intercept of 3
y = 0x + 3
y = 3
p has infinite slope and no y intercept.
x = -5
FALSE. You'd have to multiply each by 12n to get rid of the denominators.