A cube can hold 525 cm of water. How many liters of water can the cube hold?

Mathematics

1 answer:

RUDIKE [14]3 years ago

5 0

525cm³ = 525 ml = 0.525 liters

Answer: 0.525 liters

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Need help asap!!!!!!!

Neporo4naja [7]

Answer:

a) Linear function

b) Linear function

c) Exponential function

d) Exponential function

Step-by-step explanation:

a) The number of hours in a day increases constantly with 60 minute intervals

b) Constant speed = same distance traveled per given time - so it's linear

c) If a population doubles every y years, it means that the population is being raised exponentially - not at a constant rate, but more each year

d) Same as c

7 0

3 years ago

The line integral of (2x+9z) ds where the curve is given by the parametric equations x=t, y=t^2, z=t^3 for t between 0 and 1. Pl

Naya [18.7K]

Let r = (t,t^2,t^3)

Then r' = (1, 2t, 3t^2)

General Line integral is:
$\int_a^b f(r) |r'| dt$

The limits are 0 to 1
f(r) = 2x + 9z = 2t +9t^3
|r'| is magnitude of derivative vector $\sqrt{(x')^2 + (y')^2 + (z')^2}$

$\int_0^1 (2t+9t^3) \sqrt{1+4t^2 +9t^4} dt$

Fortunately, this simplifies nicely with a 'u' substitution.

Let u = 1+4t^2 +9t^4

du = 8t + 36t^3 dt

$\int_0^1 \frac{2t+9t^3}{8t+36t^3} \sqrt{u} du \\ \\ \int_0^1 \frac{2t+9t^3}{4(2t+9t^3)} \sqrt{u} du \\ \\ \frac{1}{4} \int_0^1 \sqrt{u} du$

After integrating using power rule, replace 'u' with function for 't' and evaluate limits:
$=\frac{1}{4} |_0^1 (\frac{2}{3}) (1+4t^2 +9t^4)^{3/2} \\ \\ =\frac{1}{6} (14^{3/2} - 1)$

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3 years ago

The graph shown represents a the rule y=x+1.5

VashaNatasha [74]

Answer:

This is the equation of a line with slope of 1 and the intercept point wit the 'y' axis is (0, 1.5)

Step-by-step explanation:

Lines have the following equation: y=mx+b, where 'm' is the slope and b is the interception with 'y' axis when 'x'=0

The attached pictures shows the equation of the line in a graph