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mr Goodwill [35]
1 year ago
6

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos

sible, reduce the final sum. 1/4=
5/12=
Mathematics
1 answer:
Gnoma [55]1 year ago
8 0

The converted fractions are 3/12 and 5/12 and the sum is 2/3

<h3>How to convert the fractions?</h3>

From the question, the fractions are given as

1/4 and 5/12

The denominators of these fractions are

4 and 12

So. we start by calculating the LCD of the denominators

So, we have

4 = 2* 2

12 = 2 * 2 * 3

This gives

LCD = 2 * 2 * 3

Evaluate

LCD = 12

This means that the common denominator must be 12

So, we have

1/4 and 5/12

Multiply 1/4 by 3/3

This gives

3/12 and 5/12

When the fractions are added, we have

3/12 + 5/12 = (3 + 5)/12

Evaluate

3/12 + 5/12 = 8/12

Reduce fraction

3/12 + 5/12 = 2/3

Hence, the sum of the fractions is 2/3

Read more about fractions at

brainly.com/question/1622425

#SPJ1

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What is the value of x if f(x) = 76
GaryK [48]

Answer:

The roots (zeros) are the  x   values where the graph intersects the x-axis. To find the roots (zeros), replace   f(x)  with  0   and solve for x  

No solution

3 0
3 years ago
Find the volume of a cylinder below . The formula for the volume of a cylinder is . The radius of the circle is represented by r
lapo4ka [179]

Answer:

The volume of the cylinder  V =  942 cm³      

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the graph

The height of the cylinder (h) = 12cm

The diameter of the cylinder d = 10cm

The radius of the cylinder

                              d = 2r

                             r = \frac{10}{2}

                             r = 5 cm

<u><em>Step(ii):-</em></u>

The Volume of the cylinder

     V = π r² h

     V = π (5)²(12)

     V = 300π cubic centimeter

     V = 300 × 3.14

    V = 942 cm³

<u><em>Final answer:-</em></u>

Volume of the cylinder  V =  942 cm³

     

3 0
2 years ago
A coffee supply store waits until the orders for its special coffee blend reach 100 pounds before making up a batch. Coffee sell
Daniel [21]
Let x represent the number of pounds of $10.75/lb coffee used in the mix.
.. 10.75x +3.25(100 -x) = 5.65*100 . . . . . . total cost of coffee blend
.. x(10.75 -3.25) = 100*(5.65 -3.25) . . . . . .separate x-terms from non-x terms
.. x = 240/7.5 = 32

32 pounds of $10.75/lb coffee should be used
68 pounds of $3.25/lb coffee should be used
7 0
3 years ago
Solve the system by substitution.
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Answer:

(2, 6)

Step-by-step explanation:

if you meant for both of the y to be the same then this should be right

8 0
2 years ago
Read 2 more answers
The maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4 parts per million (ppm). A consumer h
Elodia [21]

Answer:

Null hypothesis : \mu \leq 0.4

Alternative hypothesis: \mu >0.4

And for this case a type of error I for this case would be reject the null hypothesis that the population mean is lower or equal than 0.4 when actually is true.

A Type I error would occur if, in fact, μ ≤ 0.4 ppm, but the results of the sampling lead to the conclusion that μ > 0.4 ppm

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.  

Type II error, also known as a "false negative" is the error of not rejecting a null  hypothesis when the alternative hypothesis is the true. Can be interpreted as the error of failing to accept an alternative hypothesis when we don't have enough statistical power

Solution to the problem

For this case we are trying to check the following hypothesis:

Null hypothesis : \mu \leq 0.4

Alternative hypothesis: \mu >0.4

And for this case a type of error I for this case would be reject the null hypothesis that the population mean is lower or equal than 0.4 when actually is true.

A Type I error would occur if, in fact, μ ≤ 0.4 ppm, but the results of the sampling lead to the conclusion that μ > 0.4 ppm

7 0
3 years ago
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