Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
A linear equation has 1 for all exponents on the placeholders
aka the equation is first degree (aka the hightest exponent on placeholders=1) so
it is linear
T=-9
Negative plus negative is positive.
Hope that helped :))
X = cos(pi/6) = √3/2
y = sin(pi/6) = 1/2
So at point (√3/2, 1/2)
Answer: 49 students
Step-by-step explanation:
2 /7 of students in a school wore shorts today. The number of students to be selected in order to get 14 students who will wear shorts to school will be:
Let the number of students that will be sampled be y. This will be:
2/7 of y = 14
2/7 × y = 14
2y/7 = 14
Cross Multiply
2y = 7 × 14
2y = 98
y = 98/2
y = 49
49 students will be selected randomly.
