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Vlad1618 [11]
1 year ago
5

I did A and B I just need help with the rest!

Mathematics
1 answer:
Rom4ik [11]1 year ago
6 0

Solution

(a) setting f(x) = 0

\begin{gathered} 3x^4-18x^3-21x^2+144x-108=0 \\  \\ (x+3)(x-1)(x-2)(x-6)=0 \\  \\ \Rightarrow x=-3,1,2,6 \end{gathered}

(b)

when x = 0

y = f(0) = -108

Hence, the height is 108

(c)

Maximum = (1.5, 15.188)

(d)

Minimum (-1.702, -300) and (4.702, -300)

(e) From the graph, the interval of increasing is

\begin{gathered} (-1.7,\frac{3}{2}),(4.7,\infty) \\  \end{gathered}

(f) From the graph, the interval of decreasing is;

(-\infty,-1.7),(\frac{3}{2},4.7)

g)

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