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trasher [3.6K]
1 year ago
14

Please help with 30!

Mathematics
1 answer:
Paladinen [302]1 year ago
4 0

The equation of the graph y= x^{3}-2x^{2} +3x-4 has no symmetry

The equation of the graph y = x^{3}-2x^{2} +3x-4

Replace y with -y in the given equation

-y = x^{3}-2x^{2} +3x-4

When replacing y with -y gives the different equation. The equation is not symmetric with respect to x axis

Replace x with -x in the given equation

y = (-x)^{3} -2(-x^{2} )-3(-x)-4

y = -x^{3}-2x^{2} +3x-4

When replacing x with -x gives the different equation. The equation is not symmetric with respect to y axis

Replace x with -x and y with -y in the equation

-y = (-x)^{3} -2(-x^{2} )-3(-x)-4

-y =  -x^{3}-2x^{2} +3x-4

When replacing x with -x and y with -y gives the different equation. The equation is not symmetry with respect to origin.

Hence, the equation of the graph y= x^{3}-2x^{2} +3x-4 has no symmetry

Learn more about symmetry here

brainly.com/question/16180199

#SPJ1

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Please Help me it’s geometry
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Answer:

Option C.

Step-by-step explanation:

Given: In \Delta OPQ,m\angle O=107^{\circ},m\angle P=28^{\circ}.

In \Delta OPQ,

m\angle O+m\angle P+m\angle Q=180^{\circ}    (Angle sum property)

107^{\circ}+28^{\circ}+m\angle Q=180^{\circ}

135^{\circ}+m\angle Q=180^{\circ}

m\angle Q=180^{\circ}-135^{\circ}

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Now,

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In a triangle, the greatest angle has largest opposite side and smallest angle has smallest opposite side. So, we conclude that

PQ>OP>QO

Therefore, the correct option is C.

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Answer:

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Step-by-step explanation:

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