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tatuchka [14]
3 years ago
9

The graph of the equation y equals 1/2 x - 3 determine the value of y for the point (4,y).

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0
The answer is b. If your problem is y=1/2x-3

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Find the y-intercept of the following equation. Simplify your answer.<br> 10x + y = 8
vredina [299]
Answer: 8

Explanation:

Form: y = mx + b

Where:
m is the slope
b is the y-intercept

We have:
10x + y = 8
y = -10x + 8

Thus, the y-intercept is 8
4 0
2 years ago
<img src="https://tex.z-dn.net/?f=0%20%3D%20%20%20-%204.9t%20%7B%7D%5E%7B2%7D%20%20%2B%2027t%20%2B%202.4" id="TexFormula1" title
marta [7]

0 =  - 4.9t {}^{2}  + 27t + 2.4
Convert decimals to fractions

0 =  -  \frac{49}{10} t {}^{2}  + 27t +  \frac{12}{5}
Multiply both sides by 10

0 =  - 49t {}^{2}  + 270t + 24
Move expression to the left.

0 + 49t {}^{2}  - 270t - 24 = 0
Remove zero.

49t {}^{2}  - 270t - 24 = 0Solve the quadratic equation.

t =  \frac{ - ( - 270) +  -  \sqrt{( - 270) {}^{2} - 4 \times 49 \times ( - 24) } }{2 \times 49}
Remove parenthesis and calculate.

t =  \frac{270 +  -  \sqrt{72900  + 4704} }{98}
Add the numbers

t =  \frac{270 +  - 77604}{98}
Separate the solutions

t =  \frac{270  +  \sqrt{77604} }{98}  \\ t =  \frac{270 -  \sqrt{77604} }{98}
The final solution are
t1 =  \frac{270 -  \sqrt{77604} }{98} , t2 =  \frac{270 +  \sqrt{77604} }{98}

7 0
3 years ago
In the adjoining figure, area of trangle ABC is
Zepler [3.9K]

Answer:

PQ=4\ cm

Step-by-step explanation:

see the attached figure with the letter D to better understand the problem

we know that

The segment side AD is the height of triangle ABC

so

Triangles PBQ and ABD are similar by AA Similarity Theorem

The area of triangle ABC is equal to

A=\frac{1}{2}(BC)(AD)

we have

A=48\ cm^2\\BC=12\ cm

substitute

48=\frac{1}{2}(12)(AD)

AD=8\ cm

Remember that

If two triangles are similar  then the ratio of its corresponding sides is proportional

so

\frac{BP}{AB}=\frac{PQ}{AD}

substitute the given values

\frac{BP}{2BP}=\frac{PQ}{8}

\frac{1}{2}=\frac{PQ}{8}

PQ=4\ cm

3 0
3 years ago
What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ​ ( 3x 2 −4 2x+3 ​ )start fraction, d, divided by, d, x
stellarik [79]

Answer:

4.

Step-by-step explanation:

We are asked to find the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1.

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}

\frac{d}{dx}(\frac{2x+3}{3x^2-4})

\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}

\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}

\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}

\frac{-6x^2-18x-8}{(3x^2-4)^2}

Therefore, our required derivative is \frac{-6x^2-18x-8}{(3x^2-4)^2}.

Now, we will substitute x=-1 in our derivative to find the required value as:

\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}

\frac{-6(1)+18-8}{(3(1)-4)^2}

\frac{-6+18-8}{(3-4)^2}

\frac{4}{(-1)^2}

\frac{4}{1}

4

Therefore, the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1 is 4.

6 0
3 years ago
Use the image to determine the height of the girl.
sergey [27]

Answer:

  72 in

Step-by-step explanation:

We know that 120 in is equal to the sum of the given height expressions.

  (9x) +(7x-8) = 120

  16x = 128 . . . . . . add 8 and simplify

  x = 8 . . . . . . . . . . divide by 16

  9x = girl's height = 9·8 = 72 . . . . inches

The height of the girl is 72 inches.

8 0
3 years ago
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