The number of cells of Staphylococcus aureus present into the open wound, which divides by binary fission once every 30 minutes, after 30 minutes, one hour and 12 hours will be 2, 4 and 1.7 × 10⁷ cells respectively.
Binary fission is the method of asexual reproduction. It is the process by which a cell divides to form two daughter cells.
According to the question, the cell divides into 2 once after every 30 minutes.
The number of cells can be calculated by the formula: 2ⁿ
(where n = number of times the cell will divide in the given time period)
Therefore after 30 minutes, number of cells = 2¹ = 2.
Similarly, after 60 minutes, number of cells = 2² = 4.
In 12 hours, the cell will divide 24 times,
Hence the number of cells will be = 2²⁴ = 1.7 × 10⁷ cells respectively.
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