Question attached as screenshot below: please help me I don't think my answer is correct, need clarifying

Pavel [41]

2p-14=4(p+5) Step 1, parentheses 2p-14=4p+20 Subtract 20 from each side of the equation 2p-34=4p Subtract 2p from each side -34=2p Divide each side by 2 -17=p

8 0

3 years ago

What is an extended proportion

NeTakaya

An extended proportion. Proportion: A proportion is a statement that two or more ratios are equal to each other. Chap 3 Day 9 Monday 102510 Page 2 Page 3 Means Extemes Property In any true proportion, the product of the means is equal to the product of the extremes. Ex. Solve for x using the.

5 0

3 years ago

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A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

3 years ago

Can somebody please give me the answer I will mark u brilliant

VARVARA [1.3K]

Answer:

x = 6.7

Step-by-step explanation:

We know that 3.5 + x = 10.2, so if we do inverse operations we can find out the value of x.

10.2 - 3.5 = 6.7

we can check our work by substituing it back in the equation for x

6.7 + 3.5 = 10.2

so now we know that x = 6.7. I hope this helps :)

7 0

3 years ago

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Solve the following quadratic equation 6x^+28x-2=2x-10

Nataliya [291]

Idk I’m sorry I just need points.
Explanation: I need to ask a question

4 0

3 years ago