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Mandarinka [93]
4 years ago
8

What is the difference of the polynomials? (8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)

Mathematics
2 answers:
Anastaziya [24]4 years ago
5 0

Answer:

8r^6s^3-5r^5s^4+r^4s^5+5r^3s^6

Step-by-step explanation:

The two given polynomials are :

(8r^6s^3-9r^5s^4+3r^4s^5) and

(2r^4s^5-5r^3s^6- 4r^5s^4)

We have to find the difference between them, so we will arrange them in order.

8r^6s^3-9r^5s^4-(-4r^5s^4)+3r^4s^5-2r^4s^5-(-5r^3s^6)

= 8r^6s^3-9r^5s^4+4r^5s^4+3r^4s^5-2r^4s^5+5r^3s^6

= 8r^6s^3-5r^5s^4+r^4s^5+5r^3s^6   ... (answer)

Dafna1 [17]4 years ago
4 0
<span>(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
= </span><span>8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 +  5r^3s^6 + 4r^5s^4
= </span>8r^6s^3 – 9r^5s^4 +  4r^5s^4 + 3r^4s^5 – 2r^4s^5 +  5r^3s^6 
= 8r^6s^3 – 5r^5s^4 + r^4s^5  +  5r^3s^6 

Hope it helps
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Step-by-step explanation:

5.

12,\:30\\\\\mathrm{Prime\:factorization\:of\:}12:\quad 2\times\:2\times\:3\\\mathrm{Prime\:factorization\:of\:}30:\quad 2\times\:3\times\:5\\\\=2\times\:2\times\:3\times\:5\\\\=60

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6,\:10\\\\\mathrm{Prime\:factorization\:of\:}6:\quad 2\times\:3\\\mathrm{Prime\:factorization\:of\:}10:\quad 2\times \:5\\\\=2\times \:3\times \:5\\\\=30

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16,\:24\\\\\mathrm{Prime\:factorization\:of\:}16:\quad 2\times \:2\times\:2\times\:2\\\mathrm{Prime\:factorization\:of\:}24:\quad 2\times\:2\times\:2\times\:3\\\\=2\times\:2\times\:2\times\:2\times\:3\\\\=48

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14,21\\\\\mathrm{Prime\:factorization\:of\:}14:\quad 2\times\:7\\\mathrm{Prime\:factorization\:of\:}21:\quad 3\times\:7\\\\=2\times\:7\times\:3\\\\=42

9.

9,15\\\\\mathrm{Prime\:factorization\:of\:}9:\quad 3\times\:3\\\mathrm{Prime\:factorization\:of\:}15:\quad 3\times\:5\\\\=3\times\:3\times\:5\\\\=45

10.

5,\:11\\\\\mathrm{Prime\:factorization\:of\:}5:\quad 5\\\mathrm{Prime\:factorization\:of\:}11:\quad 11\\\\=5\times \:11\\\\=55

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Median (Q2): 15

Upper Quartile (Q3): 26

Maximum: 34

Interquartile Range: 17

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