Jk=8x+6
J=(8x+6)/k
kL=6x+20
L=(6x+20)/k
JL=(8x+6)/k * (6x+20)/k
=(48x²+196x+120)/k²
Answer:
A) Irrational, because it is not a terminating or repeating decimal.
Step-by-step explanation:
Every time a square root results in a decimal, it will always never end, and never repeat. The square root of 35 qualifies for both of these qualities, therefore, making the answer (A). Hope this helps!
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Answer: 34
I hope this helped!
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- Zack Slocum
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Answer:
1. Proved down
2. proved down
3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5
Step-by-step explanation:
Let us explain how to solve the question
∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1
→ That means we have an arithmetic sequence with constant
difference -5 and first term -20
1. → f(1) means we need to find the second term, which equal the
term - 5
∵ f(1) means n = 1
∴ f(1) = f(1 - 1) - 5
∴ f(1) = f(0) - 5
∵ f(0) = -20
∴ f(1) = -20 - 5 → Proved
2. → f(3) means we need to find the third term, which equal the
second term - 5
∵ f(3) means n = 3
∴ f(3) = f(3 - 1) - 5
∴ f(3) = f(2) - 5
→ f(2) = f(1) - 5
∵ f(1) = -20 - 5
∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5
∴ f(3) = [-20 - 5 - 5] - 5
∴ f(3) = -20 - 5 - 5 - 5 → Proved
3. → From 1 and 2 we notice that the number of -5 is equal to n,
at n = 1 there is one (-5), when n= 3 there are three (-5)
∵ n = 10
∴ There are ten (-5)
∴ f(10) = -20 - 5(10)
∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved
<span>To get the Least Common Multiple (LCM) of 37 and 12 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
<span><span>37: 37</span><span>12: 223 </span><span>LCM: 22337</span></span>The Least Common Multiple (LCM) is: 2 x 2 x 3 x 37 = 444</span><span> </span>
