To do this, you got to square 256.
The square root of 256 is 16.
Therefore, there are 16 small squares on each edge of the mosaic.
Kinda proof:
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25 squares. Square root is 5. 5 along each edge. My work shares same concept.
Extremely unnecessary proof:
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There are 256 squares, and you can count 16 on each edge. this shows 16 times 16, or 16 squared, which is 256.
Answer:
512
Step-by-step explanation:
Suppose we ask how many subsets of {1,2,3,4,5} add up to a number ≥8. The crucial idea is that we partition the set into two parts; these two parts are called complements of each other. Obviously, the sum of the two parts must add up to 15. Exactly one of those parts is therefore ≥8. There must be at least one such part, because of the pigeonhole principle (specifically, two 7's are sufficient only to add up to 14). And if one part has sum ≥8, the other part—its complement—must have sum ≤15−8=7
.
For instance, if I divide the set into parts {1,2,4}
and {3,5}, the first part adds up to 7, and its complement adds up to 8
.
Once one makes that observation, the rest of the proof is straightforward. There are 25=32
different subsets of this set (including itself and the empty set). For each one, either its sum, or its complement's sum (but not both), must be ≥8. Since exactly half of the subsets have sum ≥8, the number of such subsets is 32/2, or 16.
The formula to find the arc length L is
L = r*theta
where r is the radius and theta is the central angle in radians (this formula will not work if theta is in degrees)
If the central angle is 1 radian, then theta = 1 and
L = r*theta
L = r*1
L = r
So the arc length is the same as the radius
Answer: Choice A) The radius of the circle
Answer:
He needs to save 90.75
Step-by-step explanation:
Take the money the vacation will cost and divide it by the number of months in a year. 1,089 ÷ 12= 90.75
Hold on let me go do my research I’ll brb .
