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jeka57 [31]
3 years ago
5

-7 pertenece a números racionales y el por qué

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
Cada número que puede expresarse como una razón de dos enteros, cuyo denominador es distinto de cero, se llama un número racional.

espero que esto ayude :)
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GETT IT RIGHT AND GET BRAINLIEST
oksian1 [2.3K]

Answer:

18

Step-by-step explanation:

58 - |-40| =

58 -40=

18

7 0
4 years ago
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Write down the equation for the following
Mice21 [21]
Grade 7 got total 88 books
No. Of books given on Friday = 63
No. Of books on Tuesday =g
g = 88 - 63
g = 25
5 0
2 years ago
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
PLEASE HELP AND ANSWER ASAP!!!!! NO WORK NEEDED TO BE SHOWN!! JUST THE ANSWER IS GOOD!!! PLEASE!!! I"LL GIVE BRAINLIEST 30 POINT
WITCHER [35]
1) (green)
A = 1/2(4+8)(6)
A = 1/2(12)(6)
A = 36

2) (pink)
A = 1/2(8+16)(14)
A = 1/2(24)(14)
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8 0
3 years ago
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Radius and a center located at (0, - 6) Which equation represents this circle?
MArishka [77]

Answer:

A.

Step-by-step explanation:

The center  is at (0, -6) so the equation is:

(x - 0)^2 + ( y + 6)^2 = r^2

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Answer is x^2 + (y + 6)^2 = 11.

7 0
3 years ago
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