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6 months ago

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The fancy restaurant Mackenzie atel at was having asale so her dinner was 80% of the original cost. Theoriginal cost of her dinn

er was $20.00. What is the saleprice?

1 answer:

Natasha_Volkova [10]6 months ago

6 0

Given data:

The original cost of dinner C=$20.00.

The sale price is 80% of the original cost.

$\begin{gathered} S=\frac{80}{100}(20)_{} \\ =0.8(20) \\ =16 \end{gathered}$

Thus, the final sale price is $16.00.

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A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.

Anastaziya [24]

Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

1.5x+3y+1.5z=21

Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

<u>A) Peanuts (x) = 3, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21$

A doesn't equal 21. On to the next one.

<u>B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21$

B also doesn't equal 21. On to the next one...

<u>C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2</u>

Everywhere you see x,y,z you replace with their value.

$1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21$

Both sides of the equation equal 21 which means C is our answer.

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Answer:

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The answer is -7x(4x-5)
Here,
If we solve,
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Then, the answer would be:
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