El área de un cuadrado es igual a 8 veces la medida de su lado. ¿Cuánto mide por lado el cuadrado ?
El Area de un Cuadrado es : A = L²
L² = 8 x L -------------> L² / L = 8 ----------> L = 8
Cada lado mide 8 unidades.
2) El triple del área de un cuadrado menos seis veces la medida de su lado es igual a cero ¿Cuánto mide por lado el cuadrado?
El Area de un Cuadrado es : A = L²
(3 x L²) - 6 L = 0
Factorizando : 3L ( L - 2 ) = 0 --------> L = 0 ; L = 2
Cada lado mide 2 unidades.
The equation 2v-41=0 can be used to find the number of visits that would make two memberships cost the same amount.
Step-by-step explanation:
Given,
Per month charges of type 1 = $86
Per visit charge = $3
Let,
v be the number of visits.
T(v) = 3v+86
Per month charges of type 2 = $45
Per visit charge = $5
P(v) = 5v+45
For same amount to be charged;
T(v) = P(v)
The equation 2v-41=0 can be used to find the number of visits that would make two memberships cost the same amount.
Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
The answer is 6.3...
the three repeats
hope this helps!
h(x) = 3^x – 2 will be negative when x is less than 0
h(2) =7
g(2)=7
This is the point they are equal
g(x)> h(x) until2
g(x)>=h(x) -2<=x<=2
Choice A
