Sidney has 2 rectangular mirrors in her house. One mirror is 36 inches long and 24 inches wide. The other is 32 inches long and 21 1/2 in wide. A. What is the perimeter of the first rectangular mirror? B. What is the combined perimeter of both mirrors? C. What is the difference of both mirrors? D. If you wanted a mirror double the sides of the second mirror, what would be the new dimensions?
we know that
The perimeter of rectangle is equal to
P=2(L+W)
where
L is the length
W is the width
Part A. What is the perimeter of the first rectangular mirror?
we have
L=36 in
W=24
so
substitute
P=2(36+24)
P=120 cm
Part B. What is the combined perimeter of both mirrors?
Find the perimeter of the second rectangular mirror
we have
L=32 in
W=21 1/2 in=21.5 in
substitute
P2=2(32+21.5)
P2=107 in
so
the cpmbined perimeter is equal to
P=P1+P2
P=120+107=227 in
Part C. What is the difference of both mirrors?
Difference=P1-P2=120-107=13 in
Part D. If you wanted a mirror double the sides of the second mirror, what would be the new dimensions?
the original dimensions of second are
L=32 in
W=21 1/2 in=21.5 in
if you dobled the sides
L=64 in
W=43 in
