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3 years ago

7

A microwave is placed on top of two boxes. one box is 4 feet 4 inches tall, the other one is 2 feet 3 inches tall, and the micro

wave is 2 feet 6 inches tall. how tall are they combined?

1 answer:

Ymorist [56]3 years ago

4 0

8 ft 13 inches in total..............

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The price of an item yesterday was $85. Today, the price rose to $119. Find the percentage increase.

skelet666 [1.2K]

Answer:

40% increase

Step-by-step explanation:

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Mrrafil [7]

The correct answer is B. Two out of every five people in the shopping center are in the clothing store.

Step-by-step explanation:

To establish this answer we have to know the total number of people that were in the Shopping Center. So, we have to add people from every store.

48+96+20+64+12=240

The result of this operation is 240 people.

Later we have to divide the total number in 5 and multiply by 2.

So, the operation is

240/5 = 48

48x2=96

According to the above, the correct answer is B. Two out of every five people in the shopping center are in the clothing store.

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3 years ago

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of </em> $cos x = cos(\frac{\pi }{6})$ <em> is </em>

<em> x = 2nπ±</em> $\frac{\pi }{6}$ <em></em>

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

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3 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

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