Question

Find the value of c that makes t^2 - 22t+ c a perfect square trinomial.

Answer 1

The expression is a perfect square trinomial if and only if c = 121.

How to get the value of c?

A perfect square trinomial is written as:

(a + b)^2 = a^2 + b^2 + 2ab

In this case, we have:

t^2 - 22t + c

We can rewrite this as:

t^2 - 2*11*t + c

Then we have:

a = t

b = -11

And we will have that:

c = b^2 = (-11)^2 = 121

Then we have:

t^2 - 2*11*t + 121

Which is a perfect square trinomial:

(t - 11)^2 = t^2 - 22t + 121

Learn more about perfect squares:

brainly.com/question/1538726

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