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vekshin1
3 years ago
15

At Glencliff High School, the photography

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0
Hacky sack club (H) - 12 = photography club

H-12= 23
H = 35
olga_2 [115]3 years ago
4 0

Answer:

23+12=

Step-by-step explanation:

you just need figure it out in your head and see what sounds right

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it would be 40000000 because there there are 7 zeroes and then you and then you multiply the two twos together and then put it in the front.

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Read 2 more answers
What is the quotient of 5/8 and 20?
ddd [48]
What is the quotient of 5/8 and 20?Quotient is the term used to name the answer of the 2 or more digits being divided with each other.Now, we have 2 different numbers. A fraction and a whole number.First thing to do is to convert 5/8 to decimal number.=> 5 / 8 = 0.625Now, we have 2 numbers that needs to be divided.=> 20 as our dividend and 0.625 as our divisor=> 20 / 0.625 = 32<span>32 is the quotient when you divide 5/8 by 20</span>
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3 years ago
Tina sends 12 text messages each day in June. A mobile phone company offers two packages. Package A: The first 100 texts each mo
Mnenie [13.5K]

Two options are given to Tina. We find how much she pays for each option, and the one in which she pays less offers the better value.

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June has 30 days, so in June, Tina sent 12*30 = 360 text messages.

Package A:

First 100 messages cost 3p, the next 100 cost $2 and after that each costs $1.

She sends 360 messages, with:

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Package B:

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Package A costs less, thus, it offers her the better value for money in 30 days.

Another example of a problem in which a person has to choose between two packages is given in brainly.com/question/10693932

6 0
3 years ago
Booneville Theater sold 1,330 tickets to Shakespearean plays last season. This season, the
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1862 tickets.

Step-by-step explanation:

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How do I solve this problem? You drive your car on a cold day (20^oF Outside) the engine overheats to about (220^oF). When you p
GaryK [48]
ln(T- \frac{20}{200})=-0.11t \\ e^{ln(T- \frac{20}{200})}=e^{-0.11t} \\ T- \frac{20}{200} =e^{-0.11t} \\ T-0.1=e^{-0.11t} \\ T=e^{-0.11t}+0.1
Then, now that we have solved for T, we can evaluate and solve for t=20 minutes.
T=e^{-0.11t}+0.1 \\ T=e^{-0.11*20}+0.1 \\ T=e^{-2.2}+0.1 \\ T=0.11+0.1 \\ T=0.21
7 0
3 years ago
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