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tia_tia [17]
2 years ago
5

Solve d = rt for r Practice problems algebra

Mathematics
2 answers:
Alborosie2 years ago
5 0

Answer:

r=\frac{d}{t}

Step-by-step explanation:

d=rt

Divide both sides by t:

\frac{d}{t}=r

r=\frac{d}{t}

Veronika [31]2 years ago
4 0

Answer: r=d/t

Step-by-step explanation:

d=rt

d/t=rt/t

r=d/t

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Find the value of each variable
kondaur [170]

Answer:

The correct answer is option C

a = 10√3, b = 5√3, c = 15 and d = 5

Step-by-step explanation:

Points to remember

The angles of a right angled triangle, 30°, 60° and 90° then sides are in the ratio, 1: √3 : 2

<u>To find the value of variables</u>

From the figure we can see 2 right angled triangle with angle 30, 60 and 90

we get, d= 5 then b = 5√3

b = 5√3  the c = 5√3 * √3 = 15

and a = 2 * 5√3 = 10√3

Therefore the correct answer is option C

a = 10√3, b = 5√3, c = 15 and d = 5

4 0
3 years ago
Read 2 more answers
Find the circumference of circle if the diameter is 7.8cm<br>​
olasank [31]

Answer:

24.5

Step-by-step explanation:

the radius is half of a diameter

so the radius is 3.9

24.5 = 2πr= 2 * π * 3.9 ≈ 24.504

4 0
3 years ago
Three semicircles are placed in a rectangle, as shown below. The length of the rectangle is 30 m . Find the area of the shaded r
Anuta_ua [19.1K]

Answer:

The area of the shaded region is: 32.25m^2

Step-by-step explanation:

Given

See attachment for rectangle and semicircles

Required

The shaded region

We have:

l =30 --- length of the rectangle

This means that the diameters of the three circles add up to 30m.

So, the diameter of 1 is:

d = l/3

d = 30/3

d = 10

The area of one circle is:

A_1 = \pi * \frac{d^2}{8}

A_1 = 3.14 * \frac{10^2}{8}

A_1 = 3.14 * \frac{100}{8}

A_1 = 39.25m^2

The area of the three circles is:

A_2 = 3 * A_1

A_2 = 3 *39.25m^2

A_2 = 117.75m^2

The area of the rectangle is:

A_3 = 30 * r

Where r is the radius of the circle

And

r =d/2

r =10/2

r =5

So, we have:

A_3 = 30 * r

A_3 = 30 * 5

A_3 = 150

So, the shaded region is:

A_4 = A_3 - A_2

A_4 = 150 - 117.75

A_4 = 32.25m^2

8 0
3 years ago
A standard deck of cards has 52 cards. If you draw one card at a time from the deck, without replacement, how many different way
oksano4ka [1.4K]

Answer:

52! ≈ 8.0658 x 10^67  

Step-by-step explanation:

52 card options for the first card

51 card options for the second

50 card options for the third

...

2 options for the 51st card

1 option for the 52nd card

52!

The earth is about 4 billion years old. It would require 126,230,400,000,000,000 copies of earth dealing one deck per second for 4 billion years to deal the whole set.

7 0
3 years ago
I need to algebraically prove that a polynomial I created is true for a project.
natta225 [31]

The factors are

(x-y)(x-y)
or
(x-y)^2

Explanation:

We need to factor the trinomial
x^2-2xy+y^2

The factors of x^2 = (x)(x)
The factors of y^2 = (y)(y)

Since the second sign is positive we are adding the factors meaning the signs of the factors need to be the same. Since the first sign is negative both signs must be negative.

The factors are

(x-y)(x-y)
or
(x-y)^2

Check by FOIL
Firsts (x)(x) = x^2
Outers (x)(-y) = -xy
Inners (-y)(x) = -xy
Lasts (-y)(-y) = y^2
combine the middle terms
(-xy)+(-xy) = -2xy

<span>x^2-2xy+y^2</span>

7 0
3 years ago
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