g'(x)=(x^2)'(f(x))+(f'(x))(x^2)
g'(x)=(2x)(f(x))+(f'(x))(x^2)
for g'(3)
g'(3)=(2(3))(f(3))+(f'(3))(3^2)
g'(3)=(6)(5)+(-2)(9)
g'(3)=30-18
g'(3)=12
Answer:
38.34
Step-by-step explanation:
You have to do the calculation and after you do it you get 38.34
Answer:
6.700
Step-by-step explanation:
rounded to the hundred would be the same ecen rounded to ten would be the same
Answer:
7; 40
Step-by-step explanation:
No symbol for the term that you are solving for . I will use β
V = βwh Divide by (wh)
V/(wh) = β
β = V/(wh)
β = 735/(21 × 5) = 7
β = 3312/(11.5 ×7.2) = 40