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7 months ago

Help! asap!! 10 points! will give brainliest!!!

Mathematics

1 answer:

Mnenie [13.5K]7 months ago

7 0

Using the Pythagorean Theorem, we have that the distance from home plate to second base is about 127 feet.

<h3>What is the Pythagorean Theorem?</h3>

The Pythagorean Theorem relates the length of the legs $l_1$ and $l_2$ of a right triangle with the length of the hypotenuse h, stating that the hypotenuse squared is the <u>sum of the legs squared</u> of the triangle, according to the following equation:

$h^2 = l_1^2 + l_2^2$

The distance between each consecutive base is of 90 feet, hence the distance from home plate to 2nd base is the hypotenuse of a <u>right triangle in which the legs are of 90 feet</u>, being the distances from home plate to 1st base and 1st base to 2nd base.

Then:

h² = 90² + 90²

h = sqrt(90² + 90²)

h = 127 feet.

The distance from home plate to second base is about 127 feet.

More can be learned about the Pythagorean Theorem at brainly.com/question/654982

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How many ways can 6 people wait in line if Tom or John need to be last in line?

Maru [420]

Answer:

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Step-by-step explanation:

8 0

2 years ago

Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a

Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force ( $\vec F$ ), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

$\vec F = \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right)$ (1)

Vector (ordered pair - polar form)

$\vec F = \left(\|\vec F\|, \theta\right)$

Sum of vectorial components (linear combination)

$\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j}$ (2)

Where:

$\|\vec F\|$ - Norm of the vector force, in newtons.

$\theta$ - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

$\hat{i}$ , $\hat{j}$ - Orthogonal axes, no unit.

If we know that $\|\vec F\| = 30\,lbf$ and $\theta = 25^{\circ}$ , then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

$\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]$

$\vec F = (27.189,12.679)\,[lbf]$

Vector (ordered pair - polar form)

$\vec F = (30\,lbf, 25^{\circ})$

Sum of vectorial components (linear combination)

$\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]$

$\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]$

8 0

2 years ago

Please help asap!! BRAINLIEST to best/right answer!

deff fn [24]

Q: What is the value of the upper quartile?

A: C 9

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6 0

3 years ago

Read 2 more answers

Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin

Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

A=0.48

B=0.13

AB=0.03

O=0.36

As we know that when A and B both are independent that

P(A and B)= P(A) X P(B)

The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here four case are possible

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

7 0

2 years ago

Question 4 (1 point)

Aleksandr-060686 [28]

2:3

6 ÷ 2 = $3 (cost of 1 pack of butter cookies)

3 x 3 = 9 (cost of 3 packs of butter cookies)

17 - 9 = 8 (cost of 4 packs of chocolate cookies)

8 ÷ 4 = 2 (cost of one pack of chocolate cookies)

5 0

3 years ago