Answer:
2144.66 cubic inches
Step-by-step explanation:
The fishbowl is shaped like a sphere the fishbowl has a diameter of 16.
What is the closest value of water in the Fishbowl in cubic inches?
From the any question, we were told to find the closest value of the water in the fishbowl in cubic inches.
This means we are to find the volume.
The volume of a sphere is given as:
4/3πr³
We are given Diameter of the fish bowl = 16 inches
Radius = Diameter/2 = 16 inches/2
= 8 inches
Hence,
Volume of the sphere (Volume of water) = 4/3 × π × 8³
= 2144.66 cubic inches
22 = 100%
26,40 = x%
26,4*100/22=120%
x=120%
120%-100%=20%
The answer is 20%
Answer:
B. 39.59
Step-by-step explanation:
So 43 degrees, you know the length of the opposite side (27) and the angle (43 degrees), the only unknown is the hypotenuse. So you're looking for a trigonometric ratio that uses the angle (all of them do, except technically the inverse don't), the opposite side, and the hypotenuse. Sine is defined as 
. So let's plug in known values:
Multiply both sides by x
divide both sides by sin(43)
Normally I would use a calculator, but in this case I'll use the approximation given in the problem of 0.682
simplify the fraction
Width: x
Length: 2x
Perimeter=2x+2x+x+x=6x
32 cm more than width means x+32
6x=x+32
5x=32
x=6.4
Dimension is 6.4×12.8 (width×length)
This work is faster rate than grading 36 assignments in 30 minutes because :
25 ÷ 20 = 1.25
1.25 hw assignment per minute
36 ÷ 30 = 1.2
1.2 hw assignments per minute
