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Vesnalui [34]
1 year ago
15

Instructions: Determine the shape and direction of the parabola formed by the given function.

Mathematics
1 answer:
Sedbober [7]1 year ago
8 0

We have the parabola with equation y = 4x².

We have to determine the shape and direction of it.

If we compare it to the standard equation y = ax² + bx + c, we can see that a = 4, b = 0 and c = 0.

As the value of a is positive, the parabola will open upward.

The parameter has an absolute value greater than 1. This means that y increases "faster" relative to x that a parabola with a = 1.

This means that the parabola will be narrow about its line of symmetry which we call vertical strecth.

Answer:

Because a is positive the parabola opens upward.

Because a has an absolute value larger than 1 the parabola is narrow about its line of symmetry which we call vertical stretch.

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Ira Lisetskai [31]

Answer:

y = 3/4x - 5

Step-by-step explanation:

An equation of a line can be written in slope-intercept form:

y = mx + b

where m is the slope and b is the y-intercept.

Let's plug in what we know.

The slope is 3/4.

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To find b, we want to plug in a value that we know is on this line: in this case, I will use the point (4, -2). Plug in the x and y values into the x and y of the standard equation.

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To find b, multiply the slope and the input of x(4)

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Now, subtract 3 from both sides to isolate b.

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Plug this into your standard equation.

y = 3/4x - 5

This is your equation. It has a slope of 3/4, and passes through (4, -2)

Hope this helps!

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Answer:

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This is your answer. If I'm right so,

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