(7/8)*(9/10)=7*9/(8*10)=63/80
Answer: The area of the sector formed by central angle AOB is 5/8 th of the total area of the circle.
Step-by-step explanation:
Let r be the radius of the circle having the center O,
⇒ The area of the circle = square unit.
And, the central angle AOB =
( since, = 180° )
Hence, the area of sector AOB
square unit.
Now,
⇒ Area of sector AOB = 5/8 × Area of the circle.
Hence, the area of the sector formed by central angle AOB is 5/8 th of the total area of the circle.
H^2 = P^2 + B^2
a. 6^2 = 2^2 + 3^2
36 = 4 + 9
36 = 13
Therefore this is not a Pythagorean triple
b.5^2 = 4^2 + 3^2
25 = 16 + 9
25 = 25
Therefore this is a phythagorean triple
Answer:
x=14
Step-by-step explanation:
(7x - 1)° + (6x - 1)° = 180°
(13x - 2)° = 180°
13x = 182°
x = 182°/13
x = 14
The answer to this is 2/3