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3 years ago

Please help lol!!!!!!!

Mathematics

2 answers:

Elena L [17]3 years ago

8 0

Answer:

That would be 4x - 3y + 5

Step-by-step explanation:

Hope this helps

Sliva [168]3 years ago

6 0

Answer:

4x+5-3y

Step-by-step explanation:

6x-2x=4x

theres nothing to do with the 5

then 4y-1y=3y

so your answer would be 4x+5-3y

Hope it helps

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Use the functions f(x) = 2x2 + 3 and g(x) = 3x + 5 to evaluate the composite function. f(g(3))

Viefleur [7K]

Answer:

Step-by-step explanation:

g(x) = 3x + 5

g(3) = 3(3) + 5

g(3) = 9 + 5

g(3) = 14

-----------------------

f(x) = 2x² + 3

f(g(3)) = 2(g(3)) + 3

f(14) = 2(14²) + 3

f(14) = 2(196) + 3

f(14) = 392 + 3

f(14) = 395

-----------------------------

f(g(3)) = 395

7 0

3 years ago

Use elimination to solve each system if equation 3x+2y=0and x-5y=17

kotykmax [81]

Answer:

$y = -3$

$x=2$

Step-by-step explanation:

$3x + 2y = 0$

$x - 5y=17$

to use the elimination you have to make one of the numbers same

$3(x-5y=17)$

and you would have to change the sign so that both of the 3x could cancel out.

New system of equation

$3x + 2y = 0$

$-3x+15y=-51$

$17y=-51$

$y = -3$

so we know the y value so now you could find the x value take one equation

$x - 5y=17$

$x +15=17$

$x = 2$

you could try it with both of the equations

$3x + 2y = 0$

$3x + - 6=0$

$3x-6=0$

$3x=6$

$x=6/3$

$x=2$

6 0

3 years ago

PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

$b^{2}$ = 825

$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0

3 years ago

What is the 72nd term of -27, -11, 5

FinnZ [79.3K]

Answer:

1109

Step-by-step explanation:

The first term is -27, and the common difference is 16.

The nth term is:

a = a₁ + d (n − 1)

a = -27 + 16 (n − 1)

a = -27 + 16n − 16

a = 16n − 43

The 72nd term is:

a = 16(72) − 43

a = 1109

5 0

3 years ago

MARK AS BRAINLIEST

Arisa [49]

Answer:

The answer to your question is 25%

Step-by-step explanation:

Data

Initial price = $2.00

Final price = $2.50

First we subtract the final price to the inicial price

increment = 2.50 - 2.00

= $0.50 It's the amount that the school increases to the community members

Now we use a rule of three to find the percent

$2.00 ---------------------- 100%

$0.50 --------------------- x

x = 0.50 x 100/2 = 50/2 = 25%

4 0

3 years ago