Problem 2
Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.
Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.
Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.
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Problem 3
The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.
The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.
If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF
Then we can say,
GH = GN + NH
GH = EF + EF
GH = 2*EF
Answer:
50
Step-by-step explanation:
Which number is greatest?
2.89 times 10 Superscript negative 8
1.997 times 10 Superscript 2
8.9 times 10 Superscript negative 6
5 times 10 Superscript negative 6
You can do that by simply measuring the main angle and then measuring each of the two angles. If you bisected the angle correctly, you will find that each of the two angles is equal to half the original.
You can measure the angle by following these steps:
1- Place the straightedge on the base of the angle.
2- Slide the protractor over it until the vertex of the angle is at the zero of the protractor.
3- Measure the angle.
If you post the work, then we might be able to help
<span>I have graphed the given coordinates of both pentagons. The reflection was across the y-axis where coordinates of Pentagon PQRST (-x,y) resulted to Pentagon P'Q'R'S'T' (x,y). The line of reflection between the pentagons was x = 0. Line of reflection is the midway between the pre-image and its reflection.</span>