By solving a system of equations, we will see that matrix X is:
![X = \left[\begin{array}{ccc}-5&9\\26&-60\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%269%5C%5C26%26-60%5Cend%7Barray%7D%5Cright%5D)
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How to find matrix X?</h3>
X will be a matrix, let's define:
![X = \left[\begin{array}{ccc}x_{11}&x_{12}\\x_{21}&x_{22}\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx_%7B11%7D%26x_%7B12%7D%5C%5Cx_%7B21%7D%26x_%7B22%7D%5Cend%7Barray%7D%5Cright%5D)
Replacing that in the given equation we will get a system of equations:
9*x₁₁ + 4*x₂₁ = -9
2*x₁₁ + 1*x₂₁ = -1
9*x₂₁ + 4*x₂₂ = -6
2*x₂₁ + 1*x₂₂ = -8
We just need to solve that system of equations.
Using the second one we can write:
2*x₁₁ + 1*x₂₁ = -1
x₂₁ = -1 - 2x₁₁
Now we can replace that in the first equation:
9*x₁₁ + 4*x₂₁ = -9
9*x₁₁ + 4*(-1 - 2x₁₁ ) = -9
9*x₁₁ - 8*x₁₁ - 4 = -9
x₁₁ = -9 + 4 = -5
Then:
x₂₁ = -1 - 2x₁₁ = -1 - 2*(-5) = -1 + 10 = 9
So we just found the first two values of the matrix, now let's find the other two.
Using the other two eqations:
9*x₂₁ + 4*x₂₂ = -6
2*x₂₁ + 1*x₂₂ = -8
We rewrite the second as:
x₂₂ = -8 - 2x₂₁
And replace that in the other one:
9*x₂₁ + 4*(-8 - 2x₂₁) = -6
x₂₁ - 32 = -6
x₂₁ = -6 + 32 = 26
Then:
x₂₂ = -8 - 2x₂₁ = -8 - 2*26 = -60
Then our matrix is:
![X = \left[\begin{array}{ccc}-5&9\\26&-60\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%269%5C%5C26%26-60%5Cend%7Barray%7D%5Cright%5D)
Learn more about systems of equations:
brainly.com/question/13729904
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