Question

A pot is being used to boil off 1 kg of water. The specific energy required to cause the phase change is 2297 kJ/kg. Assuming the stovetop supplies 20 kJ/s to the water and the liquid is at boiling temperature, how long will it take to vaporize half of the water? Report your answer in seconds to the nearest whole number don't knou 2 attemots

Answer 1

Answer:

It will take 58 seconds

Step-by-step explanation:

If you have 1 kg of water in the jar, half of it will be 0.5 kg.

To vaporize half of the water (0.500 kg) the energy supply needed is

$2297 kJ/kg*0.5kg=1148.5 kJ$

If the stove is supplying 20 kJ/s, the time its needed is

$\frac{1148.5 kJ}{20\frac{KJ}{s} }=57.425 s$

It will last at least 58 seconds to vaporize half of the water.