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soldier1979 [14.2K]
1 year ago
12

Which function below has the end behavior f(x) →-infinity as x → infinity and f (x) → infinity as x→-infinity

Mathematics
1 answer:
Sholpan [36]1 year ago
6 0

To find the function that has the following end behavior:

\begin{gathered} f(x)\rightarrow-\infty\text{ as }x\rightarrow\infty \\ f(x)\rightarrow\infty\text{ as }x\rightarrow-\infty \end{gathered}

Considering the function which is given in option C.

When x tends to infinity,

\begin{gathered} f\mleft(x\mright)=-x^3-4x^2+x \\ \lim _{x\to\infty}(-x^3-4x^2+x)=-\infty \\ \lim _{x\to-\infty}(-x^3-4x^2+x)=\infty \end{gathered}

In other words, the degree of the given function is 3.

That is, odd.

The leading coefficient is -1.

That is, negative.

Hence, the end behavior is,

\begin{gathered} f(x)\rightarrow-\infty\text{ as }x\rightarrow\infty \\ f(x)\rightarrow\infty\text{ as }x\rightarrow-\infty \end{gathered}

Hence, the correct option is C.

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Step by step solution :

Step  1  :

           12

Simplify   ——

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Equation at the end of step  1  :

       12

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Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  x  as the denominator :

          62     62 • x

    62 =  ——  =  ——————

          1        x  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

62 • x - (12)     62x - 12

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      x              x    

Step  3  :

Pulling out like terms :

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Equation at the end of step  3  :

 2 • (31x - 6)

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Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

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Now, on the left hand side, the  x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2  •  (31x-6)  = 0

Equations which are never true :

4.2      Solve :    2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

4.3      Solve  :    31x-6 = 0

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                     31x = 6

Divide both sides of the equation by 31:

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Answer :

                  x = 6/31 = 0.194

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