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soldier1979 [14.2K]
1 year ago
12

Which function below has the end behavior f(x) →-infinity as x → infinity and f (x) → infinity as x→-infinity

Mathematics
1 answer:
Sholpan [36]1 year ago
6 0

To find the function that has the following end behavior:

\begin{gathered} f(x)\rightarrow-\infty\text{ as }x\rightarrow\infty \\ f(x)\rightarrow\infty\text{ as }x\rightarrow-\infty \end{gathered}

Considering the function which is given in option C.

When x tends to infinity,

\begin{gathered} f\mleft(x\mright)=-x^3-4x^2+x \\ \lim _{x\to\infty}(-x^3-4x^2+x)=-\infty \\ \lim _{x\to-\infty}(-x^3-4x^2+x)=\infty \end{gathered}

In other words, the degree of the given function is 3.

That is, odd.

The leading coefficient is -1.

That is, negative.

Hence, the end behavior is,

\begin{gathered} f(x)\rightarrow-\infty\text{ as }x\rightarrow\infty \\ f(x)\rightarrow\infty\text{ as }x\rightarrow-\infty \end{gathered}

Hence, the correct option is C.

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Here are summary statistics for randomly selected weights of newborn​ girls: nequals202​, x overbarequals28.3 ​hg, sequals6.1 hg
Lorico [155]

Answer:

The confidence interval is 27.5 hg less than mu less than 29.1 hg

(A) Yes, because the confidence interval limits are not similar.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = 28.3 hg

sd = 6.1 hg

n = 202

degree of freedom = n-1 = 202-1 = 201

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

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95% confidence interval is (27.5, 29.1)

When mean is 28.3, sd = 6.1 and n = 202, the confidence limits are 27.5 and 29.1 which is different from 27.8 and 29.6 which are the confidence limits when mean is 28.7, sd = 1.8 and n = 17

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