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Gemiola [76]
2 years ago
6

Triangle JKL with vertices J(1,-1), K(2,3), and L(3,-2) in the line x=4 ANSWER RIGHT NOW BEEN WAITING AN HOUR NOW

Mathematics
1 answer:
Monica [59]2 years ago
3 0

Answer:

hahhahahqhqhqhhajajahahahahahwhwhwhwhwh

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How do I convert standard form to point slope
Fittoniya [83]

The point-slope form:

y-y_1=m(x-x_1)

(x_1,\ y_1) - given point

m - given slope

The standard form:

Ax+By=C


y-y_1=m(x-x_1)    <em>use distributive property</em>

y-y_1=mx-mx_1      <em>add y_1 to both sides</em>

y=mx-mx_1+y_1      <em>subtract mx from both sides</em>

-mx+y=-mx_1+y_1       <em>change the signs</em>

mx-y=mx_1-y_1

8 0
3 years ago
The mass of a freight train is 9.98 ⋅ 106 kilograms. The mass of an aircraft carrier is 7.3 ⋅ 107 kilograms. Approximately how m
shutvik [7]
Mass of freight train: 9.98 • 106
= 1057.88 kg
mass of aircraft carrier: 7.3 • 107
= 781.1 kg
difference: 1057.88 - 781.1
= 276.78 kg
= 2.7678 x 10^2
8 0
2 years ago
QUICK PLS I ONLY HAVE 7 MINS LEFT
Vikentia [17]

Answer:

first one

Step-by-step explanation:

8 0
3 years ago
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(x+6)x-3)help me pleases
Oksanka [162]
X^2 +3x - 18 is the answer
8 0
3 years ago
A new neighborhood activity complex is being built in erie. The perimeter of the rectangular playing field is 256 yards. The len
maw [93]

Answer:

The length of the rectangular playing field is 84 yards and the width is 44 yards

Step-by-step explanation:

Let

x ------> the length of the rectangular playing field

y -----> the width of the rectangular playing field

we know that

The perimeter of the rectangular playing field is equal to

P=2(x+y)

P=256\ yd

so

256=2(x+y) ------> equation A

we have that

x=2y-4 -----> equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

256=2(2y-4+y)

128=3y-4

3y=128+4

3y=132

y=44

Find the value of x

x=2(44)-4=84

therefore

The length of the rectangular playing field is 84 yards and the width is 44 yards

4 0
3 years ago
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