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1 year ago

Given: GC bisects FGH. Determine the missing measurea. m

Mathematics

1 answer:

Keith_Richards [23]1 year ago

4 0

a. Since GC bisects FGH and the angle FGH = 122°, we know that the angle FGC = 122/2 = 61°

b. Since GC bisects FGH and the angle CGH = 42°, we know that the angle FGH = 2*42 = 84°

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What is the correct solution to 1/2(x+18)=4(2x-6)-9x

denis-greek [22]

Answer:

x = 22

Step-by-step explanation:

I interpreted your problem as:

$\frac{1}{2} (x+18) = 4(2x-6)-9x$

I simplified the problem to:

$\frac{1}{2} x+9 = 8x-24-9x$

I combined like terms:

$\frac{1}{2} x+9 = -x-24$

I moved all x to one side and all other constants to the other:

$\frac{3}{2} x = -33$

I divided by 3/2 (1.5) on both sides to isolate x:

$x = 22$

Hope it helps! (:

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3 years ago

A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

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2 years ago

Prime numbers less than 50

SVETLANKA909090 [29]

Answer:

2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,83,89,97

Step-by-step explanation:

those are the prime numbers

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2 years ago

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The area of a trapezium is 384cm². Its parallel sides are in the ratio3 : 5 and the perpendicular distance between them is 12 cm

Pani-rosa [81]

Area of trapezium=384 square cm
Ratio of parallel sides=
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3 years ago