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Bingel [31]
1 year ago
7

Given: GC bisects FGH. Determine the missing measurea. m

Mathematics
1 answer:
Keith_Richards [23]1 year ago
4 0

a. Since GC bisects FGH and the angle FGH = 122°, we know that the angle FGC = 122/2 = 61°

b. Since GC bisects FGH and the angle CGH = 42°, we know that the angle FGH = 2*42 = 84°

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If u, v, and w are nonzero vectors in r 2 , is w a linear combination of u and v?
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Not necessarily. \mathbf u and \mathbf v may be linearly dependent, so that their span forms a subspace of \mathbb R^2 that does not contain every vector in \mathbb R^2.

For example, we could have \mathbf u=(0,1) and \mathbf v=(0,-1). Any vector \mathbf w of the form (r,0), where r\neq0, is impossible to obtain as a linear combination of these \mathbf u and \mathbf v, since

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3 years ago
(4 pts) If a rock is thrown vertically upward from the surface of Mars with an initial velocity of 15m/sec
Yuliya22 [10]

Answer:

Step-by-step explanation:

I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.

The position equation is

s(t)=-1.86t^2+15t  That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.

The first derivative of position is velocity:

v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):

0 = -3.72t + 15 and solve for t:\

-15 = -3.72t so

t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:

s(4.03) = -1.86(4.03)² + 15(4.03) so

s(4.03) = 30.2 meters.

Calculus is amazing. Much easier than most methods to solve problems like this.

7 0
2 years ago
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