Answer:
The answer is $13! Hope this helps!
Step-by-step explanation:
Assuming he works every week of the year. 40hrs a week×52 weeks a year=2,080 hours. $27,040 / 2,080 hours equals $13 an hour!
It is false
when you imagine or draw the picture of the polygon and try to cut into halves diagonally you'll get an uneven amount of piece
i hoped I helped and plz give me brainlist
Answer:
3-pack= 135 cupcakes
6-pack= 270 cupcakes
9-pack= 405 cupcakes
Step-by-step explanation:
Let's say that 3-pack = a, 6-pack =b and 9-pack = c
The company’s leaders want to divide the cupcakes so that 3-pack, 6-pack and 9-pack packages produced are the same. This translate to an equation of:
a=b=c
The factory has 810 cupcakes in total. The equation will be:
a*3 + b*6 + c *9= 810
3a + 6b + 9c = 810
If we substitute the 1st equation into the second(we can put b=a and c=a), the equation will become
3a + 6b + 9c = 810
3a + 6(a) + 9(a) = 810
18a= 810
a=45
Using the first equation, we know that we have 45 packages of each kind.
If there are 45 packages of 3-pack, the number of cupcakes go into 3-package will be: 3*45= 135 cupcakes
If there are 45 packages of 6-pack, the number of cupcakes go into 6-package will be: 6*45= 270 cupcakes
If there are 45 packages of 9-pack, the number of cupcakes go into 9-package will be: 9*45= 405 cupcakes
Answer:
Wavelengths of all possible photons are;
λ1 = 9.492 × 10^(-8) m
λ2 = 1.28 × 10^(-6) m
λ3 = 1.28 × 10^(-6) m
λ4 = 4.04 × 10^(-6) m
Step-by-step explanation:
We can calculate the wavelength of all the possible photons emitted by the electron during this transition using Rydeberg's equation.
It's given by;
1/λ = R(1/(n_f)² - 1/(n_i)²)
Where;
λ is wavelength
R is Rydberg's constant = 1.0974 × 10^(7) /m
n_f is the final energy level = 1,2,3,4
n_i is the initial energy level = 5
At n_f = 1,.we have;
1/λ = (1.0974 × 10^(7))(1/(1)² - 1/(5)²)
1/λ = 10535040
λ = 1/10535040
λ = 9.492 × 10^(-8) m
At n_f = 2,.we have;
1/λ = (1.0974 × 10^(7))(1/(2)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.21)
1/λ = 2304540
λ = 1/2304540
λ = 4.34 × 10^(-7) m
At n_f = 3, we have;
1/λ = (1.0974 × 10^(7))(1/(3)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.07111)
1/λ = 780373.3333333334
λ = 1/780373.3333333334
λ = 1.28 × 10^(-6) m
At n_f = 4, we have;
1/λ = (1.0974 × 10^(7))(1/(4)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.0225)
1/λ = 246915
λ = 1/246915
λ = 4.04 × 10^(-6) m
