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1 year ago

Choose all that apply 3/4 ÷ 1/81/66243/4•1/83/4•8/14/3•8/1

Mathematics

1 answer:

GarryVolchara [31]1 year ago

5 0

Explanation:

The steps to divide fractions are KCF:

• K,eep the first fraction as it is

• C,hange the division sign to a multiplication sign

• F,lip the second fraction:

$\begin{gathered} \frac{3}{4}\div\frac{1}{8}= \\ \frac{3}{4}\times\frac{8}{1}= \\ \frac{3\times8}{4\times1}=\frac{24}{4}=6 \end{gathered}$

Here we can see which ones apply

Answer:

• 6

• 3/4 • 8/1

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Answer:

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Step-by-step explanation:

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2 years ago

During a recent rainstorm, 8 centimeters of rain fell in Dubaku's hometown, and 2.36 centimeters of rain fell in Elliot's hometo

Nostrana [21]

Answer:

5.64 cm

Step-by-step explanation:

Required:How much more rain fell in Dubaku's town than in Elliot's town?

8 centimeters of rain fell in Dubaku's hometown

2.36 centimeters of rain fell in Elliot's hometown

We are asked to find how much more rain fell in Dubaku's town than in Elliot's town so it is calculated as the difference between the rain in both of there towns and is given by:

Difference in rain= 8-2.36

Difference in rain= 5.64 cm.

Therefore, 5.64 cm of more rain fell in Dubaku's town than in Elliot's town.

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3 years ago

The Equation is 34 + 4 ⋅ 5 = ____. (input whole numbers only)

solong [7]

Answer:

Step-by-step explanation:

34 + 4 ⋅ 5 (by PEDMAS, do multiply first)

= 34 + 20

= 54

4 0

3 years ago

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uranmaximum [27]

Answer:

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Step-by-step explanation:

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3 years ago

Brainliest will be given to the correct answer!

IrinaK [193]

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for $b_{1}$ . $b_{1} = \frac{2\cdot A}{h}-b_{2}$

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from $b_{1}$ and $b_{2}$ to $b$ . $b = \frac{A}{h}$

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

$A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})$ (Eq. 1)

Where:

$h$ - Height of the trapezoid, measured in centimeters.

$b_{1}$ , $b_{2}$ - Lengths fo the bases, measured in centimeters.

$A$ - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})$ Definition of division.

3) $2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}]$ Compatibility with multiplication/Commutative and associative properties.

4) $h = \frac{2\cdot A}{b_{1}+b_{2}}$ Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that $A = 91\,cm^{2}$ , $b_{1} = 16\,cm$ and $b_{2} = 12\,cm$ , then height of the trapezoid is:

$h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}$

$h = 6.5\,cm$

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for $b_{1}$ :

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})$ Definition of division.

3) $2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})$ Compatibility with multiplication/Commutative and associative properties.

4) $2\cdot A \cdot h^{-1} = b_{1}+b_{2}$ Existence of multiplicative inverse/Modulative property

5) $\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}$ Definition of division/Compatibility with addition/Commutative and associative properties

6) $b_{1} = \frac{2\cdot A}{h}-b_{2}$ Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for $b_{1}$ .

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ( $A= 215\,cm^{2}$ , $h = 8.6\,cm$ and $b_{2} = 30\,cm$ )

$b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm$

$b_{1} = 20\,cm$

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from $b_{1}$ and $b_{2}$ to $b$ . Now we present the procedure to clear $b$ below:

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $b_{1} = b_{2}$ Given.

3) $A = \frac{1}{2}\cdot h \cdot (2\cdot b)$ 2) in 1)

4) $A = 2^{-1}\cdot h\cdot (2\cdot b)$ Definition of division.

5) $A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b$ Commutative and associative properties/Compatibility with multiplication.

6) $b = A \cdot h^{-1}$ Existence of multiplicative inverse/Modulative property.

7) $b = \frac{A}{h}$ Definition of division/Result.

8 0

4 years ago