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Mrac [35]
4 years ago
15

Find the quotient. Answer to the nearest hundredth. 437 ÷ 15

Mathematics
2 answers:
lutik1710 [3]4 years ago
6 0

Answer:

29.13

Step-by-step explanation:

29.1333

29.13

nirvana33 [79]4 years ago
5 0
It is 29.13 percent
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In the diagram, AE = 2AC and ∠BAC ≅ ∠DAE. What additional information is necessary to prove that ΔABC is similar to ΔADE, using
ss7ja [257]

Since you want to use the SAS theorem, you must find sides that are either side of angles BAC and DAE. You have already made use of sides AE and AC, so the other sides you need to choose are AB and AD. The appropriate relationship for similarity is ...

... AD = 2AB

since you want the sides of triangle ADE to be twice then length of those in triangle ABC.

7 0
3 years ago
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Which is the solution of the equation a + 2 = 10?
Alexandra [31]

Hey there!

a + 2 = 10

SUBTRACT 2 to BOTH SIDES

a + 2 - 2 = 10 - 2

CANCEL out: 2 - 2 because that gives you 0

KEEP: 10 - 2 because that helps solve for the a-value

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Answer: Option C. a = 8

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Describe at least two similarities between constructing a perpendicular line through a point on a line and constructing a perpen
Sophie [7]

Two similarities between constructing a perpendicular line through a point on a line and constructing a perpendicular through a point off a line are;

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Description:

1. One of the first steps is to place the compass on the point and from

point, draw arcs to intersect or cross the given line at two points.

2. The compass is placed at each of the intersection point in step 1 and

(opened a little wider when constructing from a point on the line) arcs are

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3. From the point of intersection of the arcs in step 2, a line is drawn with a

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2 years ago
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The perimeter would be ≈ 36.797836892947.

Rounded would be about 37, or 36.8.

Hope this helps!!!!

P=4a

d\sqrt{2a}

Solving for P:

P=2\sqrt{2d} =2*\sqrt{2*13.01}≈36.79784

Hope this helps!!

8 0
4 years ago
Devin, sebastian, carlos, and Federico completed a heist in GTA coming them $580,500. Devin carns 30%
AURORKA [14]

Answer:

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