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galina1969 [7]
2 years ago
5

Prove the formula sin 3 A + sin A = 4 sin A cos2A

Mathematics
1 answer:
pantera1 [17]2 years ago
5 0

We proved that formula using the trigonometry relations sin3A + sinA = 4sinAcos^2A.

In the given question,

We have to prove the formula sin 3A+sin A = 4sinAcos^2A

The given expression is sin 3A+sin A = 4sinAcos^2A

To prove the formula we take the left side terms to the right side terms

The left side is sin 3A+sin A.

As we know that sin 3A = 3sinA − 4sin^3A

To solve the left side we put the value of sin 3A in sin 3A+sin A.

=sin 3A+sin A

=3sinA − 4sin^3A+sin A

Simplifying

= (3sinA+sin A) − 4sin^3A

= 4sinA − 4sin^3A

Taking 4sinA common from both terms

= 4sinA(1 − sin^2A)

As we know that cos^2A=1 − sin^2A. So

= 4sinAcos^2A

We proved the right hand side.

To learn more about formula of trigonometry terms link is here

brainly.com/question/15270423

#SPJ1

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<h3>Correct Response;</h3>
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