Total amount of students=72
p(dance)=9/72
divide both numerator and denominator with 9
1/8
The experimental probability is 1/8
The minimum number of games Enzo could have played is 5
Answer:
1) P(0) = 5000
2) P(t --> ∞) = 25000
Step-by-step explanation:
P(t) = (25t² + 125t + 200)/(t² + 5t + 40)
1) Population at the moment corresponds to population at t = 0
P(0) = (25(0²) + 125(0) + 200)/(0² + 5(0) + 40) = (0 + 0 + 200)/(0 + 0 + 40) = 5 thousand = 5000 (P was stated to be in thousands)
2) Population in the long term corresponds to the population as t --> ∞
P(t) = (25t² + 125t + 200)/(t² + 5t + 40)
Divide through the numerator and denominator by t²
P(t) = (25 + (125/t) + (200/t²))/(1 + 5/t + (40/t²))
P(t --> ∞) = (25 + 0 + 0)/(1 + 0 + 0) (Since, (1/∞) = 0)
P(t --> ∞) = 25 thousand = 25000
Given:
Total number of marbles in the bag = 150
There are 21 blue marbles for every 4 white marbles.
To find:
The number of blue marbles in the bag.
Solution:
Since, there are 21 blue marbles for every 4 white marbles, therefore the ratio of blue marble to white marbles is 21:4.
Let the number of blue marbles be 21x and white marbles be 4x.
Total number of marbles in the bag = 150
Divide both sides by 25.
Now,
Therefore, the number of blue marbles is 126.
Answer: It may possibly be SU
Step-by-step explanation:
