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Nat2105 [25]
3 years ago
11

Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beat

riz had won the same number of total tickets. What is the minimum number of games that Enzo could have played?
Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0
Enzo could have had 5
exis [7]3 years ago
3 0
The minimum number of games Enzo could have played is 5
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Evaluate 4a if a =2 so what is the answer
eimsori [14]

Answer:

The answer is 8.

Step-by-step explanation:

hope that helps

4a

4(2)

=8

4 0
3 years ago
(6.3x10^0)-(5x10^-2) <br><br> and also<br><br> (7x10^-3)+(8x10^-1)
Mekhanik [1.2K]
1. 6.25 x 10^0
2. 8.07 x 10^-1
5 0
3 years ago
X2/y+x2/ for x=6,y=-4 and z=-2
hodyreva [135]
X2/y+x2/
x=6
y=-4
z=-2

6✖️2/-4➕6✖️2
6✖️2=12
This goes for both due to PEMDAS
Now it looks like this:
12/-4➕12

-4➕12= 8

Now it looks like this:
12/8

Since there was no z then -2 wouldn’t be needed

So your answer would be 12/8

Hope this helps! :3
5 0
4 years ago
What is the mass of 20 gallons of gasoline?
Tomtit [17]
Your answer would be 14.978
3 0
4 years ago
PLEASE HELP QUICK
mezya [45]

Answer:

74

Step-by-step explanation:

Using linear equations, we are given two equations from the questions:

4x +7y=30 from day one and 3x +5y=22 from day two

Multiply the first equation by 3 and second by 4 giving us

12x +21y=90 and 12x +20y=88. Minus both equations.

12x - 12x +21y - 20y= 90 - 88, Gives you y=2,

You can now use the value of y to find x.

4x + 7y = 30

4x + 7(2)= 30

4x + 14= 30. Minus 14 on both sides giving you

4x=16. Divide both sides by 4.

x=4

Now use both values to find how much money is needed on the third day.

10x + 17y

=10(4) + 17(2)

=40 +34

=74

8 0
3 years ago
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