Question

Begging for HELP please been working on thus for 3 days and just can't make it click. please help

Answer 1

The analysis of the given functions is as follows;

i. y = 16ˣ ⇒ Graph C

ii. y = 0.25ˣ ⇒ Graph B

iii. y = 4.5ˣ ⇒ Graph D

iv. y = 0.5ˣ ⇒ Graph A

v. y = 10·x + 1 ⇒ Graph E

(b) The equation of the exponential function is; y = 0.375ˣ

(c) The equation of the line is; y = 10·x - 4

(d) y = 25ˣ

(e) The equation of the perpendicular line is; y ≈ 5 - 0.1·x

What are exponential functions?

An exponential function in which the argument is the index value such that the power to which a constant is raised, is the argument.

i. The values of the function y = 16ˣ is given by the function that has a value of 4 when x = 0.5, which corresponds with the graph C

ii. The function, y = 0.25ˣ decreases as the value of x increases, from negative to positive which corresponds to the graph B

iii. The function y = 4.5ˣ has a value of 4.5 when x = 1, which corresponds with the graph D

iv. The function, y = 0.5ˣ also decreases as x increases and has a value of  5 when x = -1, which corresponds to the graph A

v. The function, y = 10·x + 1 is a linear function which corresponds with the graph E

(b) The exponential function of graph A and B are y = 0.5ˣ and y = 0.25ˣ respectively

An exponential function that lies between graph A and graph B is obtained by adjusting the y-intercept value to be between 0.5 and 0,25 as follows;

$y =\left(\dfrac{ 0.5 + 0.25}{2}\right)^x = 0.375^x$

The exponential function that is located between  graph A and B is 0.375ˣ

(c) The equation of the function of graph E is; y = 10·x  + 1, which is of the form y = m·x + c

Where comparing, we get, m = 10 = The slope of the graph

The slope of parallel lines are congruent, therefore, the slope of the line parallel to the line E is also 10

The equation of the line passing through (0, -4), and parallel to the graph E in point and slope form is y - (-4) = 10·(x - 0)

y + 4 = 10·x

The equation of the line is; y = 10·x - 4

(d) An equation for an exponential function with a higher constant percent rate than graph C, y = i6ˣ is y = 25ˣ

(e) The slope of the line perpendicular to the line E, y = 10·x + 1, that has a slope m, is found as follows;

$m_{\perp} = -\dfrac{1}{m}$

$m_{\perp} = -\dfrac{1}{10} = -0.1$
The equation of the line is therefore; y - 5 = -0.1 × (x - 0)

y = -0.1·x + 5 = 5 - 0.1·x

The equation of the line perpendicular to line E  is y = 5 - 0.1·x

Learn more about the graph of functions here:

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