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3 years ago

Please help i am confusion

Mathematics

2 answers:

frez [133]3 years ago

8 0

I think 6 is h & 4 is k

Nonamiya [84]3 years ago

8 0

Answer:

h=40 and k=10

Step-by-step explanation:

Simultaneous equation!!!

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V + –79 = –89 solving for v

Tasya [4]

-89 + 79= -10
So v=-10

3 0

3 years ago

Read 2 more answers

Solve the equation. Show the process, not just an answer. 6.EE.7

Natalka [10]

Isolate the variable, note the equal sign, what you do to one side, you do to the other.

1) 4k = 24

Isolate the variable, k. Divide 4 from both sides of the equation:

(4k)/4 = (24)/4

k = 24/4

k = 6

2) 34 + h = 60

Isolate the variable, h. Subtract 34 from both sides of the equation:

34 (-34) + h = 60 (-34)

h = 60 - 34

h = 26

3) 1/5x = 30

Isolate the variable, x. Multiply 5 to both sides of the equation:

(5) * (1/5)x = (30) * (5)

x = 30 * 5

x = 150

4) m - 42 = 85

Isolate the variable, m. Add 42 to both sides of the equation:

m- 42 (+42) = 85 (+42)

m = 85 + 42

m = 127

6 0

3 years ago

Pls help me with this

Julli [10]

Answer:

8125, im pretty sure this is right

Step-by-step explanation:

4 0

3 years ago

How did the transformation of ()=f of , open x close . equals , x squared to ()=−g of , open x close . equals , x squared , minu

Nikolay [14]

The intercepts are the points where the graph crosses the x or y-axis

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3

The functions are given as:

$f(x) = x^2$

$g(x) = x^2 - 3$

Function f(x)

$f(x) = x^2$

The x-intercept is calculated as follows:

Set f(x) to 0

$x^2 = 0$

Solve for x

$x = 0$

The y-intercept is calculated as follows:

Set x to 0

$f(0) = 0^2$

$f(0) = 0$

Hence, the intercepts are 0

Function g(x)

$g(x) = x^2 - 3$

The x-intercept is calculated as follows:

Set g(x) to 0

$x^2 - 3 = 0$

Solve for x

$x^2 = 3$

$x = \±\sqrt 3$

The y-intercept is calculated as follows:

Set x to 0

$g(x) = x^2 - 3$

$g(0) = 0^2 - 3$

$g(0) = - 3$

The x-intercepts are $\±\sqrt 3$ , while the y-intercept is -3

By comparing the intercepts of f(x) and g(x),

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3